如何通过jquery ajax发送AntiForgeryToken(CSRF)和FormData

Question

所以我想通过AJAX POST与fileUpload一起使用AntiForgeryToken.这是我的代码:

视图

@using (Html.BeginForm("Upload", "RX", FormMethod.Post, new {id = "frmRXUpload", enctype = "multipart/form-data"}))
{
     @Html.AntiForgeryToken()
     @Html.TextBoxFor(m => m.RXFile, new {.type = "file"})
     ...rest of code here
}

<script>
    $(document).ready(function(){
        $('#btnRXUpload').click(function () {
            var form = $('#frmRXUpload')

            if (form.valid()) {
                var formData = new FormData(form);
                formData.append('files', $('#frmRXUpload input[type="file"]')[0].files[0]);
                formData.append('__RequestVerificationToken', fnGetToken());

                $.ajax({
                    type: 'POST',
                    url: '/RX/Upload',
                    data: formData,
                    contentType: false,
                    processData: false
                })
            }
        })
    })
</script>

调节器

[HttpPost]
[ValidateAntiForgeryToken]
public ActionResult Upload()
{
    //rest of code here
}

我明白了

防伪令牌无法解密.如果此应用程序由Web场或群集托管

通过提琴手的错误.不知道如何解决这个问题？

我发现了答案:

<script>
        $(document).ready(function(){
            $('#btnRXUpload').click(function () {
                var form = $('#frmRXUpload')

                if (form.valid()) {
                    var formData = new FormData(form.get(0)); //add .get(0)
                    formData.append('files', $('#frmRXUpload input[type="file"]')[0].files[0]);

                    $.ajax({
                        type: 'POST',
                        url: '/RX/Upload',
                        data: formData,
                        contentType: false,
                        processData: false
                    })
                }
            })
        })
    </script>

Answer 1

最后发现答案:

我只需要.get(0)在表单中添加,这里是代码:

<script>
        $(document).ready(function(){
            $('#btnRXUpload').click(function () {
                var form = $('#frmRXUpload')

                if (form.valid()) {
                    var formData = new FormData(form.get(0)); //add .get(0)
                    formData.append('files', $('#frmRXUpload input[type="file"]')[0].files[0]);
                    //formData.append('__RequestVerificationToken', fnGetToken()); //remark this line

                    $.ajax({
                        type: 'POST',
                        url: '/RX/Upload',
                        data: formData,
                        contentType: false,
                        processData: false
                    })
                }
            })
        })
    </script>