cir*_*cey 2 mysql multiple-tables
cid | category
1 | desserts
2 | cakes
3 | biscuits
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id | recipe_name | cid | iid
1 | black forest cake | 1,2 | 1,2,3,4
2 | angel cake | 2 | 1,2,4
3 | melting moments | 3 | 2,5
4 | croquembouche | 1,3 | 1,5
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iid | ingredient_name
1 | self-raising flour
2 | milk
3 | chocolate
4 | baking powder
5 | plain flour
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我能够使用cid拉取某些食谱来查询数据库,即.甜点:
SELECT * FROM recipe_name WHERE cid='1'
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但是,我如何创建一个列表,如下面的成分列出<br>?
黑森林蛋糕:
自发面粉
牛奶
巧克力
发酵粉
我是新手,所以请原谅任何愚蠢的问题!
在单个逗号分隔字段中存储多值属性几乎总是一个坏主意.它使一切都很难查询.
相反,您可能需要考虑使用两个新的交集表来重构您的模式.
这两个表保持原样(只是更改了recipe_categoryto的名称,categories以便不与交集表冲突):
CREATE TABLE categories (
cid int NOT NULL PRIMARY KEY,
category_name varchar(50)
) ENGINE=INNODB;
CREATE TABLE ingredients (
iid int NOT NULL PRIMARY KEY,
ingredient_name varchar(50)
) ENGINE=INNODB;
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recipe_name按如下所示修改表,删除cid和iid字段:
CREATE TABLE recipe_name (
id int NOT NULL PRIMARY KEY,
recipe_name varchar(50)
) ENGINE=INNODB;
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然后,您可以使用以下两个交集表定义多值关系:
CREATE TABLE recipe_ingredients (
recipe_id int NOT NULL,
ingredient_id int NOT NULL,
PRIMARY KEY (recipe_id, ingredient_id),
FOREIGN KEY (recipe_id) REFERENCES recipe_name (id),
FOREIGN KEY (ingredient_id) REFERENCES ingredients (iid)
) ENGINE=INNODB;
CREATE TABLE recipe_categories (
recipe_id int NOT NULL,
category_id int NOT NULL,
PRIMARY KEY (recipe_id, category_id),
FOREIGN KEY (recipe_id) REFERENCES recipe_name (id),
FOREIGN KEY (category_id) REFERENCES categories (cid)
) ENGINE=INNODB;
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现在让我们用您的示例数据填充这些表:
INSERT INTO categories VALUES (1, 'desserts');
INSERT INTO categories VALUES (2, 'cakes');
INSERT INTO categories VALUES (3, 'biscuits');
INSERT INTO ingredients VALUES(1, 'self-raising flour');
INSERT INTO ingredients VALUES(2, 'milk');
INSERT INTO ingredients VALUES(3, 'chocolate');
INSERT INTO ingredients VALUES(4, 'baking powder');
INSERT INTO ingredients VALUES(5, 'plain flour');
INSERT INTO recipe_name VALUES(1, 'black forest cake');
INSERT INTO recipe_name VALUES(2, 'angel cake');
INSERT INTO recipe_name VALUES(3, 'melting moments');
INSERT INTO recipe_name VALUES(4, 'croquembouche');
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要定义配方及其成分和类别之间的关系,您需要按如下方式填充交集表:
INSERT INTO recipe_categories VALUES (1, 1);
INSERT INTO recipe_categories VALUES (1, 2);
INSERT INTO recipe_categories VALUES (2, 2);
INSERT INTO recipe_categories VALUES (3, 3);
INSERT INTO recipe_categories VALUES (4, 1);
INSERT INTO recipe_categories VALUES (4, 3);
INSERT INTO recipe_ingredients VALUES (1, 1);
INSERT INTO recipe_ingredients VALUES (1, 2);
INSERT INTO recipe_ingredients VALUES (1, 3);
INSERT INTO recipe_ingredients VALUES (1, 4);
INSERT INTO recipe_ingredients VALUES (2, 1);
INSERT INTO recipe_ingredients VALUES (2, 2);
INSERT INTO recipe_ingredients VALUES (2, 3);
INSERT INTO recipe_ingredients VALUES (3, 2);
INSERT INTO recipe_ingredients VALUES (3, 5);
INSERT INTO recipe_ingredients VALUES (4, 1);
INSERT INTO recipe_ingredients VALUES (4, 5);
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最后,构建查询将非常简单:
SELECT i.ingredient_name
FROM recipe_ingredients ri
JOIN ingredients i ON (i.iid = ri.ingredient_id)
WHERE ri.recipe_id = (SELECT id
FROM recipe_name
WHERE recipe_name = 'Black Forest Cake');
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结果:
+--------------------+
| ingredient_name |
+--------------------+
| self-raising flour |
| milk |
| chocolate |
| baking powder |
+--------------------+
4 rows in set (0.00 sec)
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然后,您可能希望<br>在应用程序代码中而不是在SQL中格式化该结果集(添加s).
但是,如果你真的希望在SQL中这样做,那么MySQL支持方便的GROUP_CONCAT()功能,可以使用如下:
SELECT GROUP_CONCAT(i.ingredient_name separator '<BR>') output
FROM recipe_ingredients ri
JOIN ingredients i ON (i.iid = ri.ingredient_id)
WHERE ri.recipe_id = (SELECT id
FROM recipe_name
WHERE recipe_name = 'Black Forest Cake');
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结果:
+----------------------------------------------------------+
| output |
+----------------------------------------------------------+
| self-raising flour<BR>milk<BR>chocolate<BR>baking powder |
+----------------------------------------------------------+
1 row in set (0.00 sec)
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转储到HTML中,你很高兴!
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