如何使用jQuery DataTables在单元格中显示超链接

Question

我将一些Ajax数据读入jQuery DataTables.问题是我需要将第一列中的数据转换为超链接.如在<td><a href = "5555.html">5555</a></td>.

我的JSON数据:

{
   "data": [
      ["5555","07/17/2010","RCC Saturday Open","E10","Harris, Fred","1900","Nikolayev, Igor (FM)","2367","1-0"],
      ["5554","07/17/2010","RCC Saturday Open","B01","Nikolayev, Igor (FM)","2367","Motroni, Richard","1728","1-0"]
   ]
}

JavaScript的:

$(document).ready(function() {
   $('#cccr').DataTable( {
      "render": function ( data, type, row ) {
         return '<a href="basic.php?game=' + data + '></a>'; //doesn't work
      },
      "ajax": 'games.json',
      "deferRender": true
   } );
} );

我对JavaScript知之甚少.在谷歌搜索datatables.net网站几小时后,我无法弄明白.

有人可以帮忙吗？

Answer 1

原因

选项render应该是任何一个子属性columns或columnDefs.

解

使用columnDefs.render选项动态显示单元格中的超链接.

例如:

var table = $('#cccr').DataTable({
    /* ... skipepd other options ... */
    columnDefs: [
        {
            targets: 0,
            render: function ( data, type, row, meta ) {
                if(type === 'display'){
                    data = '<a href="basic.php?game=' + encodeURIComponent(data) + '">' + data + '</a>';
                }

                return data;
            }
        }
    ]      
});

DEMO

有关代码和演示,请参阅此jsFiddle.

Answer 2

render通过选项配置列定义：

"render": function ( data, type, row ) {
  return '<a href="#">' + data + '</a>';
}