蟒蛇.如何从ax,y列表和偏移距离获取偏移样条的x,y坐标

efi*_*ida 5 python graphics curve spline offset

我需要制作翼型轮廓曲线的偏移平行外壳,但我无法弄清楚如何使所有点与所需距离处的主轮廓曲线上的点等距.

这是我的示例翼型轮廓 在此输入图像描述

这是我最好的,也不是好方法 在此输入图像描述

编辑 @Patrick解决方案距离0.2 在此输入图像描述

Pat*_*pin 6

您将需要无限/零的特殊情况斜率,但基本方法是使用插值计算某点的斜率,然后找到垂直斜率,然后计算该距离处的点.

我已经从这里修改了示例以添加第二个图形.它适用于您提供数据文件,但您可能需要更改其他信封的符号计算.

编辑根据你关于想要信封连续的评论,我在最后添加了一个俗气的半圆,非常接近为你做这个.基本上,当创建信封时,圆形和更凸的可以制作它,它会更好地工作.此外,您需要重叠开头和结尾,否则您将有差距.

而且,它几乎可以肯定会变得更有效率 - 我不是一个笨拙的专家,所以这只是纯粹的Python.

def offset(coordinates, distance):
    coordinates = iter(coordinates)
    x1, y1 = coordinates.next()
    z = distance
    points = []
    for x2, y2 in coordinates:
        # tangential slope approximation
        try:
            slope = (y2 - y1) / (x2 - x1)
            # perpendicular slope
            pslope = -1/slope  # (might be 1/slope depending on direction of travel)
        except ZeroDivisionError:
            continue
        mid_x = (x1 + x2) / 2
        mid_y = (y1 + y2) / 2

        sign = ((pslope > 0) == (x1 > x2)) * 2 - 1

        # if z is the distance to your parallel curve,
        # then your delta-x and delta-y calculations are:
        #   z**2 = x**2 + y**2
        #   y = pslope * x
        #   z**2 = x**2 + (pslope * x)**2
        #   z**2 = x**2 + pslope**2 * x**2
        #   z**2 = (1 + pslope**2) * x**2
        #   z**2 / (1 + pslope**2) = x**2
        #   z / (1 + pslope**2)**0.5 = x

        delta_x = sign * z / ((1 + pslope**2)**0.5)
        delta_y = pslope * delta_x

        points.append((mid_x + delta_x, mid_y + delta_y))
        x1, y1 = x2, y2
    return points

def add_semicircle(x_origin, y_origin, radius, num_x = 50):
    points = []
    for index in range(num_x):
        x = radius * index / num_x
        y = (radius ** 2 - x ** 2) ** 0.5
        points.append((x, -y))
    points += [(x, -y) for x, y in reversed(points)]
    return [(x + x_origin, y + y_origin) for x, y in points]

def round_data(data):
    # Add infinitesimal rounding of the envelope
    assert data[-1] == data[0]
    x0, y0 = data[0]
    x1, y1 = data[1]
    xe, ye = data[-2]

    x = x0 - (x0 - x1) * .01
    y = y0 - (y0 - y1) * .01
    yn = (x - xe) / (x0 - xe) * (y0 - ye) + ye
    data[0] = x, y
    data[-1] = x, yn
    data.extend(add_semicircle(x, (y + yn) / 2, abs((y - yn) / 2)))
    del data[-18:]

from pylab import *

with open('ah79100c.dat', 'rb') as f:
    f.next()
    data = [[float(x) for x in line.split()] for line in f if line.strip()]

t = [x[0] for x in data]
s = [x[1] for x in data]


round_data(data)

parallel = offset(data, 0.1)
t2 = [x[0] for x in parallel]
s2 = [x[1] for x in parallel]

plot(t, s, 'g', t2, s2, 'b', lw=1)

title('Wing with envelope')
grid(True)

axes().set_aspect('equal', 'datalim')

savefig("test.png")
show()
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sub*_*ean 6

如果您愿意(并且能够)安装第三方工具,我强烈推荐使用Shapely模块。这是一个向内和向外偏移的小样本:

from StringIO import StringIO
import matplotlib.pyplot as plt
import numpy as np
import requests
import shapely.geometry as shp

# Read the points    
AFURL = 'http://m-selig.ae.illinois.edu/ads/coord_seligFmt/ah79100c.dat'
afpts = np.loadtxt(StringIO(requests.get(AFURL).content), skiprows=1)

# Create a Polygon from the nx2 array in `afpts`
afpoly = shp.Polygon(afpts)

# Create offset airfoils, both inward and outward
poffafpoly = afpoly.buffer(0.03)  # Outward offset
noffafpoly = afpoly.buffer(-0.03)  # Inward offset

# Turn polygon points into numpy arrays for plotting
afpolypts = np.array(afpoly.exterior)
poffafpolypts = np.array(poffafpoly.exterior)
noffafpolypts = np.array(noffafpoly.exterior)

# Plot points
plt.plot(*afpolypts.T, color='black')
plt.plot(*poffafpolypts.T, color='red')
plt.plot(*noffafpolypts.T, color='green')
plt.axis('equal')
plt.show()
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这是输出;注意向内偏移上的“领结”(自相交)是如何自动删除的: 在此处输入图片说明