检查varchar中的字符

Question

如何检查varchar是否包含来自另一个varchar的所有字符,其中字符序列无关紧要？

例如:我在表中有varchar @a = 'ABC'和column 'Col','Table'其中是row 'Col' = 'CBAD'.我想选择这一行,因为它包含@a变量中的所有字符.请帮忙.

我试过这样的事情:

DECLARE @a varchar(5) = 'ABCD'
DECLARE @b varchar(5) = 'DCA'

DECLARE @i int = 0

DECLARE @pat varchar(30) = ''
while @i <> len(@b) BEGIN
    SET @i = @i + 1
    SET @pat = @pat + '[' + @a + ']'
END

SELECT @pat

IF @b LIKE @pat SELECT 1
ELSE SELECT 0

但我不能说这个WHERE条件

Answer 1

您首先需要将要检查的变量拆分为行,并删除重复项.对于只有几个字符,您可以简单地使用表值构造函数:

DECLARE @b varchar(5) = 'DCA';
SELECT  DISTINCT Letter = SUBSTRING(@b, n.Number, 1)
FROM (VALUES(1),(2),(3),(4),(5),(6),(7),(8),(9),(10)) AS n (Number)
WHERE n.Number <= LEN(@b)

这使:

Letter
----------
D
C
A   

现在,您可以将其与列进行比较,并将其仅限于列包含所有字母的列(在HAVING子句中完成)

DECLARE @b varchar(5) = 'DCA';

WITH Letters AS
(   SELECT  DISTINCT Letter = SUBSTRING(@b, n.Number, 1)
    FROM (VALUES(1),(2),(3),(4),(5),(6),(7),(8),(9),(10)) AS n (Number)
    WHERE n.Number <= LEN(@b)
)
SELECT  *
FROM    (VALUES ('AA'), ('ABCD'), ('ABCDEFG'), ('CAB'), ('NA')) AS t (Col)
WHERE   EXISTS
        (   SELECT  1
            FROM    Letters AS l
            WHERE   t.Col LIKE '%' + l.Letter + '%'
            HAVING  COUNT(DISTINCT l.Letter) = (SELECT COUNT(*) FROM Letters)
        );

如果您的变量可能超过10个字符,那么您可能需要采用稍微不同的字符串拆分方法.我仍然会使用数字来做这个,但是会使用Itzik Ben-Gan的叠加CTE方法:

WITH N1 AS (SELECT N FROM (VALUES(1),(1),(1),(1),(1),(1),(1),(1),(1),(1)) AS n (N)),
N2 (N) AS (SELECT 1 FROM N1 AS N1 CROSS JOIN N1 AS N2),     
N3 (N) AS (SELECT 1 FROM N2 AS N1 CROSS JOIN N2 AS N2)
SELECT  ROW_NUMBER() OVER(ORDER BY N)
FROM    N3;

这将为您提供1到10,000的一组数字,您可以根据需要添加更多CTE和交叉连接以扩展该过程.所以使用更长的字符串你可能会:

DECLARE @b varchar(5) = 'DCAFGHIJKLMNEOPNFEDACCRADFAE';

WITH N1 AS (SELECT N FROM (VALUES(1),(1),(1),(1),(1),(1),(1),(1),(1),(1)) AS n (N)),
N2 (N) AS (SELECT 1 FROM N1 AS N1 CROSS JOIN N1 AS N2),     
N3 (N) AS (SELECT 1 FROM N2 AS N1 CROSS JOIN N2 AS N2),
Numbers (Number) AS (SELECT TOP (LEN(@b)) ROW_NUMBER() OVER(ORDER BY N) FROM N3),
Letters AS (SELECT DISTINCT Letter = SUBSTRING(@b, n.Number, 1) FROM Numbers AS n)
SELECT  *
FROM    (VALUES ('ABCDDCAFGHIJKLMNEOPNFEDACCRADFAEEFG'), ('CAB'), ('NA')) AS t (Col)
WHERE   EXISTS
        (   SELECT  1
            FROM    Letters AS l
            WHERE   t.Col LIKE '%' + l.Letter + '%'
            HAVING  COUNT(DISTINCT l.Letter) = (SELECT COUNT(*) FROM Letters)
        );

Answer 2

你可以尝试这样:

SELECT * FROM yourTable where colname like '%[A]%' 
                        AND colname like '%[B]%'
                        AND colname like '%[C]%'

或者您可以尝试使用PATINDEX

SELECT * FROM yourTable WHERE PATINDEX('%[ABC]%',colname) > 1