如何嘲笑mock内部方法

Question

目标.php

<?php

class Target
{
    public function validate()
    {
        $this->getData();
        return true;
    }

    public function getData()
    {
        return array();
    }
}

目标测试.php

<?php

class TargetTest extends PHPUnit_Framework_TestCase
{
    public function testValidate()
    {
        $mock = m::mock('Target');
        $mock->shouldReceive('getData')
            ->once();
        $expected = $this->exp->validate();

        $this->assertTrue($expected);
    }
}

结果

Mockery\Exception\InvalidCountException: Method getData() from Mockery_1_ExpWarning should be called exactly 1 times but called 0 times.

我使用Mockery作为模拟工具，示例总是关于如何模拟DI，我想知道我可以模拟内部方法吗？

Answer 1

您可以使用测试框架的部分模拟功能仅模拟getData方法并描述期望。

作为（工作）示例：

use Mockery as m;

class TargetTest extends \PHPUnit_Framework_TestCase
{
    public function testValidate()
    {
        $mock = m::mock('Target[getData]');
        $mock->shouldReceive('getData')
            ->once();
        $expected = $mock->validate();

        $this->assertTrue($expected);
    }
}

希望这有帮助