我本质上是试图修改此答案,以编程方式为每个变量级别的图生成块。
但是,在我的特定情况下,我传递了一个用于后续子集的字符向量,这似乎是代码失败的根源。
# My report (test.Rmd)
```{r}
library(ggplot2)
library(knitr)
data(diamonds)
diamonds$cut <- factor(gsub(" ", "_", diamonds$cut)) # Get rid of spaces
cut.levels <- levels(diamonds$cut)
```
## Generate report for each level of diamond cut
```{r, include=FALSE}
src <- lapply(cut.levels, function(cut) knit_expand(file = "template.Rmd"))
```
`r knit(text = unlist(src))`
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和模板(template.Rmd):
```{r, results='asis', echo = FALSE}
cat("### {{cut}} cut")
```
```{r {{cut}}-cut, eval = FALSE}
with(subset(diamonds, cut == "{{cut}}"),
plot(carat, price, main = paste("{{cut}}", "cut"))
)
```
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将其与template.Rmd中的第二个块一起运行以eval=FALSE产生预期的输出-每个块的一系列标头以及所回显的代码。但是,调用中cut.levels字符串的替换值subset丢失了引号,我希望在eval=FALSE删除块选项时会导致以下错误:
Quitting from lines 6-8 (test.Rmd)
Quitting from lines 12-12 (test.Rmd)
Error in eval(expr, envir, enclos) : object 'Fair' not found
Calls: <Anonymous> ... with -> subset -> subset.data.frame -> eval -> eval
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现在正在查找对象,Fair而不是使用的记录cut == "Fair"。
谢谢你的协助!
> sessionInfo()
R version 3.2.1 (2015-06-18)
Platform: x86_64-w64-mingw32/x64 (64-bit)
Running under: Windows 7 x64 (build 7601) Service Pack 1
locale:
[1] LC_COLLATE=English_United States.1252 LC_CTYPE=English_United States.1252
[3] LC_MONETARY=English_United States.1252 LC_NUMERIC=C
[5] LC_TIME=English_United States.1252
attached base packages:
[1] stats graphics grDevices utils datasets methods base
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我看到两个问题。
首先,正如您所指出的那样,它{{cut}}被扩展为不带引号,因此您需要将标签用引号引起来。其次,您的结束日期plot()被放错了位置。它应与以下编辑一起运行:
### {{cut}} cut
```{r {{cut}}-cut}
with(subset(diamonds, cut == "{{cut}}"),
plot(carat, price, main = paste("{{cut}}", "cut"))
)
```
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