Sen*_* SP 4 java mongodb aggregation-framework spring-data-mongodb
有谁知道如何使用Spring-data将以下聚合函数转换为java代码?
db.myCollection.aggregate([
{$match:{"status" : {$in:["WORKING","UNASSIGNED"]}}},
{$group:{
_id:{
"status":"$status",
"queue":"$queueName"
},
"count":{$sum:1},
"oldest":{$min:"$queueTime"},
"slow":{$sum:{$cond:[
{$lte: ["$queueServiceTs", new Date()]},
1,
0]}
}
}
}
]);
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Spring mongo目前不支持:
所以第二种情况是在这种情况下会破坏聚合辅助函数的使用.你可以通过先做一个来解决这个问题$project,但这需要一个影响性能的额外执行阶段.
但您可以做的是创建自己的抽象类,该类在标准构建器函数中工作,但允许您使用标准对象构建管道阶段:
public class CustomGroupOperation implements AggregationOperation {
private DBObject operation;
public CustomGroupOperation (DBObject operation) {
this.operation = operation;
}
@Override
public DBObject toDBObject(AggregationOperationContext context) {
return context.getMappedObject(operation);
}
}
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然后您可以将它与标准构建器一起使用,如下所示:
Aggregation aggregation = newAggregation(
new CustomGroupOperation(
new BasicDBObject("$group",
new BasicDBObject("_id",
new BasicDBObject("status","$status")
.append("queue","$queueName")
)
.append("count",new BasicDBObject("$sum",1))
.append("oldest", new BasicDBObject("$min","$queueTime"))
.append("slow",
new BasicDBObject("$sum",
new BasicDBObject("$cond",Arrays.asList(
new BasicDBObject("$lte",Arrays.asList(
"$queueServiceTs",
new Date()
)),
1,
0
))
)
)
)
)
);
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并且与$group您定义的阶段完全一致地构建管道.
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