我的阵列: -
var data = [
[4, "Shailesh ", "Sharma"],
[5, "Devesh Kumar ", "Neema"],
[6, "Vardan S ", "Khanna"],
[208, "Kamlesh ", "Lohiya"],
[210, "Raj Bahadur ", "Singh"]
]
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您可以使用以下方式执行此操作jQuery.each():
var data = [
[4, "Shailesh ", "Sharma"],
[5, "Devesh Kumar ", "Neema"],
[6, "Vardan S ", "Khanna"],
[208, "Kamlesh ", "Lohiya"],
[210, "Raj Bahadur ", "Singh"]
]
$.each(data, function (i, n) {
$.each(n, function (i2, n2) {
console.log(i2, n2);
});
});
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编辑:
用于添加选项从数组中获取数据
var option = '';
$.each(data, function (i, n) {
option += '<option value="' + n[0] + '">' + n[1] + '</option>';
});
console.log(option);
$('select').append(option);
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