如何在JSON对象中获取JSON数组？

Question

这是我的JSON

{
    "data": [
        {
            "id": 1,
            "Name": "Choc Cake",
            "Image": "1.jpg",
            "Category": "Meal",
            "Method": "",
            "Ingredients": [
                {
                    "name": "1 Cup Ice"
                },
                {
                    "name": "1 Bag Beans"
                }
            ]
        },
        {
            "id": 2,
            "Name": "Ice Cake",
            "Image": "dfdsfdsfsdfdfdsf.jpg",
            "Category": "Meal",
            "Method": "",
            "Ingredients": [
                {
                    "name": "1 Cup Ice"
                }
            ]
        }
    ]
}

这就是我获取id的方式,这部分名称在获取JSON的第一部分时工作得很好

//getting whole json string
JSONObject jsonObj = new JSONObject(jsonStr);

//extracting data array from json string
JSONArray ja_data = jsonObj.getJSONArray("data");
int length = jsonObj .length(); 

//loop to get all json objects from data json array
for(int i=0; i<length; i++) 
{
    JSONObject jObj = ja_data.getJSONObject(i);
    Toast.makeText(this, jObj.getString("Name"), Toast.LENGTH_LONG).show();

    // getting inner array Ingredients
    JSONArray ja = jObj.getJSONArray("Ingredients");
    int len = ja.length();


} 

现在我正试图让成分不确定这是我一直在尝试的

//getting whole json string
JSONObject jsonObj = new JSONObject(jsonStr);

//extracting data array from json string
JSONArray ja_data = jsonObj.getJSONArray("data");
int length = jsonObj .length(); 

//loop to get all json objects from data json array
for(int i=0; i<length; i++) 
{
    JSONObject jObj = ja_data.getJSONObject(i);
    Toast.makeText(this, jObj.getString("Name"), Toast.LENGTH_LONG).show();

    // getting inner array Ingredients
    JSONArray ja = jObj.getJSONArray("Ingredients");
    int len = ja.length();

    // getting json objects from Ingredients json array
    for(int j=0; j<len; j++)
    {
        JSONObject json = ja.getJSONObject(j);
        Toast.makeText(this, json.getString("name"), Toast.LENGTH_LONG).show();
    }
} 

但是不行不通怎样才能得到它？

Answer 1

我想这会对你有所帮助.

JSONObject jsonObj = new JSONObject(jsonStr);

JSONArray ja_data = jsonObj.getJSONArray("data");
int length = jsonObj.length();
for(int i=0; i<length; i++) {
  JSONObject jsonObj = ja_data.getJSONObject(i);
  Toast.makeText(this, jsonObj.getString("Name"), Toast.LENGTH_LONG).show();

  // getting inner array Ingredients
  JSONArray ja = jsonObj.getJSONArray("Ingredients");
  int len = ja.length();

  ArrayList<String> Ingredients_names = new ArrayList<>();
  for(int j=0; j<len; j++) {
    JSONObject json = ja.getJSONObject(j);
    Ingredients_names.add(json.getString("name"));
  }
}

Answer 2

JSONObject jsonObject =new JSONObject(jsonStr);
JSONArray jsonArray = jsonObject.getJSONArray("data");
for(int i=0;i<jsonArray.length;i++){
    JSONObject json = jsonArray.getJSONObject(i);
    String id = json.getString("id");
    String name=json.getString("name");
    JSONArray ingArray = json.getJSONArray("Ingredients") // here you are going   to get ingredients
    for(int j=0;j<ingArray.length;j++){
        JSONObject ingredObject= ingArray.getJSONObject(j);
        String ingName = ingredObject.getString("name");//so you are going to get   ingredient name
        Log.e("name",ingName); // you will get 
   }
}

Answer 3

解决了,使用字符串数组列表从Ingredients获取名称.使用以下代码:

JSONObject jsonObj = new JSONObject(jsonStr);

//extracting data array from json string
JSONArray ja_data = jsonObj.getJSONArray("data");
int length = ja_data.length();

//loop to get all json objects from data json array
for(int i=0; i<length; i++){
    JSONObject jObj = ja_data.getJSONObject(i);
    Toast.makeText(this, jObj.getString("Name"), Toast.LENGTH_LONG).show();
    // getting inner array Ingredients
    JSONArray ja = jObj.getJSONArray("Ingredients");
    int len = ja.length();
    ArrayList<String> Ingredients_names = new ArrayList<>();
    for(int j=0; j<len; j++){
        JSONObject json = ja.getJSONObject(j);
        Ingredients_names.add(json.getString("name"));
    }
}