从String中设置Symfony2中的DateTime和Time

Question

在我的实体中,我有两个字段,一个是DateTime,另一个是Time.

我正在尝试这样做:

$time = "05:45";
$date = "01-09-2015"

$entity = new Entity();
$entity->setDate(new \DateTime($date));
$entity->setTime($time);

在这两种情况下,Symfony都告诉我代码格式有问题.

我也尝试过:

->setDate(new Datetime($date));
->setDate(DateTime::createFromFormat($date, 'd-m-Y));
->setTime(strtotime($time));

始终具有相同的结果.

如果有人能帮助我,我会感激的.

谢谢

---

更新

现在,我试过了

$date = strtotime($date);
$time = strtotime($time);
$entity->setDate(date("d-m-Y", $date));
$entity->setTime(date("H:i",$time));

Symfony告诉我:

错误:在非对象上调用成员函数format()

in vendor/doctrine/dbal/lib/Doctrine/DBAL/Types/TimeType.php at line 53   -
    public function convertToDatabaseValue($value, AbstractPlatform $platform)
    {
        return ($value !== null)
            ? $value->format($platform->getTimeFormatString()) : null;
    }
    /**

我也试过这个:

$dateObject = new DateTime();
$date = $dateObject->format('d-m-Y');
$time = $dateObject->format('H:i');
$entity->setDate($date);
$entity->setTime($time);

而symfony告诉我:

Attempted to call method "format" on class "Symfony\Component\Validator\Constraints\DateTime". On line "$date = $dateObject->format('Y-m-d');"

谢谢您的帮助

---

更新 - 解决

最后,昨天解决了这个问题,用这个:

$entity->new Entity();
$entity->setDate(\DateTime::createFromFormat('d-m-Y',$date));
$entity->setTime(\DateTime::createFromFormat('H:i',$time));

谢谢!

Answer 1

Symfony不知道在哪里找到DateTime类,因此它在错误的(默认)命名空间中进行搜索.使用领先\.

而且你在format函数中反转了参数和time参数createFromFormat().

所以你的代码变成:

$time = "05:45";
$date = "01-09-2015"

$entity = new Entity();
$entity->setDate(\DateTime::createFromFormat('d-m-Y', $date));
$entity->setTime(\DateTime::createFromFormat('H:i', $time));

顺便说一句,你确定你真的需要在你的实体中分割日期和时间吗？这取决于你的情况,但你可以这样做(只需要操作一个对象):

$time = "05:45";
$date = "01-09-2015"

$entity = new Entity();
$entity->setDateTime(\DateTime::createFromFormat('d-m-Y H:i', $date.' '.$time));