iOS是静态还是动态框架？

Question

这可能听起来像一个愚蠢的问题,但如果你有一个thirdParty.framework文件,你能告诉它是静态的还是动态的？我的意思是,如果你看里面,他们看起来不一样吗？

Answer 1

它可以是.

但是,只有iOS8 +才允许在应用程序包中使用动态框架.

找出的方法是查看.framework并使用file主文件上的命令:

$ cd iOS/Crashlytics.framework
$ ls -l
total 9984
-rwxr-xr-x  1 andy  staff  4710656 11 Sep 17:11 Crashlytics
drwxr-xr-x  8 andy  staff      272 11 Sep 17:11 Headers
-rw-r--r--  1 andy  staff     1553 11 Sep 17:11 Info.plist
drwxr-xr-x  3 andy  staff      102 11 Sep 17:11 Modules
-rwxr-xr-x  1 andy  staff   146164 11 Sep 17:11 run
-rwxr-xr-x  1 andy  staff   241688 11 Sep 17:11 submit
$ file Crashlytics 
Crashlytics: Mach-O universal binary with 5 architectures
Crashlytics (for architecture armv7):   current ar archive random library
Crashlytics (for architecture armv7s):  current ar archive random library
Crashlytics (for architecture i386):    current ar archive random library
Crashlytics (for architecture x86_64):  current ar archive random library
Crashlytics (for architecture arm64):   current ar archive random library

其中的ar archive意思是"静态库".

或者,"动态"框架将如下所示,并明确声明它是动态链接的.

$ cd /Library/Frameworks/iTunesLibrary.framework/
$ ls -l
total 40
lrwxr-xr-x  1 root  wheel   24 10 Sep 17:38 Headers -> Versions/Current/Headers
lrwxr-xr-x  1 root  wheel   24 10 Sep 17:38 Modules -> Versions/Current/Modules
lrwxr-xr-x  1 root  wheel   26 10 Sep 17:38 Resources -> Versions/Current/Resources
drwxr-xr-x  4 root  wheel  136 10 Sep 17:41 Versions
lrwxr-xr-x  1 root  wheel   22 10 Sep 17:38 XPCServices -> Versions/A/XPCServices
lrwxr-xr-x  1 root  wheel   30 10 Sep 17:38 iTunesLibrary -> Versions/Current/iTunesLibrary
$ file Versions/Current/iTunesLibrary 
Versions/Current/iTunesLibrary: Mach-O universal binary with 2 architectures
Versions/Current/iTunesLibrary (for architecture i386): Mach-O dynamically linked shared library i386
Versions/Current/iTunesLibrary (for architecture x86_64):   Mach-O 64-bit dynamically linked shared library x86_64

Answer 2

我使用此命令从带有框架列表的路径中列出所有 STATIC 框架：

find -E . -type f -iregex ".*\.framework\/[^./]*" -exec file {} \; | grep ': current ar archive' | sed 's/.*\/\(.*.framework\).*/\1/'