如果我找到你,你想做这样的事情:
import java.util.function.DoubleSupplier;
public class Test {
enum MathConstants {
PI(Test::getPi), E(Test::getE);
private final DoubleSupplier supply;
private MathConstants(DoubleSupplier supply) {
this.supply = supply;
}
public double getValue() {
return supply.getAsDouble();
}
}
public static void main(String... args) {
System.out.println(MathConstants.PI.getValue());
}
public static double getPi() {
return Math.PI;
}
public static double getE() {
return Math.E;
}
}
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如果所有getter的返回类型相同,则不是很困难.考虑以下PoJo类:
public static class MyPoJo {
final String foo, bar;
public MyPoJo(String foo, String bar) {
this.foo = foo;
this.bar = bar;
}
public String getFoo() {
return foo;
}
public String getBar() {
return bar;
}
public int getBaz() {
return 5;
}
}
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然后我们可能有这样的枚举:
public static enum Getters {
FOO(MyPoJo::getFoo), BAR(MyPoJo::getBar);
private final Function<MyPoJo, String> fn;
private Getters(Function<MyPoJo, String> fn) {
this.fn = fn;
}
public String getValue(MyPoJo object) {
return fn.apply(object);
}
}
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并像这样使用它:
System.out.println(Getters.FOO.getValue(new MyPoJo("fooValue", "barValue"))); // fooValue
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但是,如果要返回不同类型,则会出现问题.在这种情况下,我建议使用带有预定义实例的普通类而不是枚举:
public static final class Getters<T> {
public static final Getters<String> FOO = new Getters<>(MyPoJo::getFoo);
public static final Getters<String> BAR = new Getters<>(MyPoJo::getBar);
public static final Getters<Integer> BAZ = new Getters<>(MyPoJo::getBaz);
private final Function<MyPoJo, T> fn;
private Getters(Function<MyPoJo, T> fn) {
this.fn = fn;
}
public T getValue(MyPoJo object) {
return fn.apply(object);
}
}
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用法是一样的:
System.out.println(Getters.FOO.getValue(new MyPoJo("fooValue", "barValue"))); // fooValue
System.out.println(Getters.BAZ.getValue(new MyPoJo("fooValue", "barValue"))); // 5
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