使用jsp条件显示html元素

Question

我想显示第二个密码输入字段,基于从数据库中读取的布尔值.从数据库中读取的代码已经编写,并且可以正常工作.我遇到的问题是条件显示列表元素.我知道jsp很少 - 谷歌搜索答案,并提出以下,女巫不工作.码:

			<ul>
				<li><label for="username">Username</label>
					<input type="username" name="username" placeholder="username" required>
				</li>
				<li><label for="password">Password</label>
					<input type="password" name="password" placeholder="password" required>
				</li>
				<!-- conditional display of a second password field -->
				<% 
					if (@showDoublePasswords == true) { 
				%>
					<li><label for="password">Password 2</label>
						<input type="password" name="password" placeholder="password" required>
					</li>
					
				<% } %>
            </ul>

Answer 1

试试这个

<ul>
                <li><label for="username">Username</label>
                    <input type="username" name="username" placeholder="username" required>
                </li>
                <li><label for="password">Password</label>
                    <input type="password" name="password" placeholder="password" required>
                </li>
                <!-- conditional display of a second password field -->
                <% 
                    //Remove '@' 
                    if (showDoublePasswords == true) 
                    { 
                %>
                      <li><label for="password">Password 2</label>
                          <input type="password" name="password" placeholder="password" required>
                    </li>

                <% } 
                %>
            </ul>

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