我使用http://jsonapi.org/格式获取此数据:
{
"data": [
{
"type": "prospect",
"id": "1",
"attributes": {
"provider_user_id": "1",
"provider": "facebook",
"name": "Julia",
"invitation_id": 25
}
},
{
"type": "prospect",
"id": "2",
"attributes": {
"provider_user_id": "2",
"provider": "facebook",
"name": "Sam",
"invitation_id": 23
}
}
]
}
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我有我的模特:
type alias Model = {
id: Int,
invitation: Int,
name: String,
provider: String,
provider_user_id: Int
}
type alias Collection = List Model
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我想将json解码为Collection,但不知道如何.
fetchAll: Effects Actions.Action
fetchAll =
Http.get decoder (Http.url prospectsUrl [])
|> Task.toResult
|> Task.map Actions.FetchSuccess
|> Effects.task
decoder: Json.Decode.Decoder Collection
decoder =
?
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我如何实现解码器?谢谢
mgo*_*old 24
试试这个:
import Json.Decode as Decode exposing (Decoder)
import String
-- <SNIP>
stringToInt : Decoder String -> Decoder Int
stringToInt d =
Decode.customDecoder d String.toInt
decoder : Decoder Model
decoder =
Decode.map5 Model
(Decode.field "id" Decode.string |> stringToInt )
(Decode.at ["attributes", "invitation_id"] Decode.int)
(Decode.at ["attributes", "name"] Decode.string)
(Decode.at ["attributes", "provider"] Decode.string)
(Decode.at ["attributes", "provider_user_id"] Decode.string |> stringToInt)
decoderColl : Decoder Collection
decoderColl =
Decode.map identity
(Decode.field "data" (Decode.list decoder))
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棘手的部分是stringToInt用于将字符串字段转换为整数.我根据什么是int以及什么是字符串来遵循API示例.我们的运气稍微有点像预期的那样String.toInt返回Result,customDecoder但是有足够的灵活性,你可以得到一些更复杂和接受两者.通常你会用map这种东西; customDecoder主要map用于可能失败的功能.
另一个技巧是用来Decode.at进入attributes子对象.