joe*_*oec 1 iphone key-value-coding uiscrollview
所以关注这个问题在这里,我创建了两组新的文件:
JCScrollViewController.m
JCScrollViewController.xib
JCKeyboard.xib
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在JCScrollViewController.xib我只有一个滚动视图,scrollView连接到.m文件的出口,视图插座连接到视图.在JCScrollViewController.m符合的UIScrollViewDelegate.
在我的app委托中,我这样做:
JCScrollViewController *viewController = [[JCScrollViewController alloc] init];
[window addSubview:viewController.view];
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在JCScrollViewController.m我这样做-viewDidLoad:
//load your JCKeyboard.xib into a UIView object
NSArray *nibParts = [[NSBundle mainBundle] loadNibNamed:@"JCKeyboard"
owner:nil
options:nil];
//first object is the view
UIView *keyboard = [nibParts objectAtIndex:0];
//add keyboard to scrollView
[scrollView addSubview:keyboard];
//set content size to same dimensions as TallView.xib
scrollView.contentSize = CGSizeMake(320, 600);
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当我启动应用程序时,我收到此错误:
this class is not key value coding-compliant for the key view.
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什么会导致这个?
谢谢
您的JCScrollViewController是否正确扩展了UIViewController?如果不确定,请显示您的头文件.
您可能在IB中有一个名为"view"的链接,而链接到的类没有名为"view"的IBOutlet - 因此错误.IB应将此显示为黄色链接.
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