从以下数据帧 df1 可以看出
Branch Loan_Amount TAT
A 100 2.0
A 120 4.0
A 300 9.0
B 150 1.5
B 200 2.0
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我可以使用聚合函数将以下输出作为数据帧 df2 获取
Branch Number_of_loans Loan_Amount Total_TAT
A 3 520 15.0
B 2 350 3.5
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我知道我可以使用 nrow 来计算 number_of_loans 并合并,但我正在寻找更好的方法。
基础包:
df1 <- aggregate(.~ Branch, df, FUN = "sum")
df2 <- setNames(aggregate(Loan_Amount~Branch, df, length)[2], c("Number_of_loans"))
cbind(df1, df2)
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输出
Branch Loan_Amount TAT Number_of_loans
1 A 520 15.0 3
2 B 350 3.5 2
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包裹
sqldf:
library(sqldf)
sqldf("SELECT Branch, COUNT(Loan_Amount) Number_of_loans, SUM(Loan_Amount) Loan_Amount, SUM(TAT) TAT
FROM df
GROUP BY Branch")
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输出
Branch Number_of_loans Loan_Amount TAT
1 A 3 520 15.0
2 B 2 350 3.5
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数据
df <- structure(list(Branch = structure(c(1L, 1L, 1L, 2L, 2L), .Label = c("A",
"B"), class = "factor"), Loan_Amount = c(100L, 120L, 300L, 150L,
200L), TAT = c(2, 4, 9, 1.5, 2)), .Names = c("Branch", "Loan_Amount",
"TAT"), class = "data.frame", row.names = c(NA, -5L))
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