hcp*_*hcp 28 c# razor asp.net-core-mvc asp.net-core
我使用RazorEngine解析我的MVC 6项目中的模板,如下所示:
Engine.Razor.RunCompile(File.ReadAllText(fullTemplateFilePath), templateName, null, model);
它适用于测试版6.它在升级到测试版7后出现错误:
MissingMethodException:找不到方法:"Void Microsoft.AspNet.Razor.CodeGenerators.GeneratedClassContext.set_ResolveUrlMethodName(System.String)".在RazorEngine.Compilation.CompilerServiceBase.CreateHost中(类型templateType,类型modelType,String className)
这是global.json:
{
"projects": [ "src", "test" ],
"sdk": {
"version": "1.0.0-beta7",
"runtime": "clr",
"architecture": "x64"
}
}
这是project.json:
...
"dependencies": {
"EntityFramework.SqlServer": "7.0.0-beta7",
"EntityFramework.Commands": "7.0.0-beta7",
"Microsoft.AspNet.Mvc": "6.0.0-beta7",
"Microsoft.AspNet.Mvc.TagHelpers": "6.0.0-beta7",
"Microsoft.AspNet.Authentication.Cookies": "1.0.0-beta7",
"Microsoft.AspNet.Authentication.Facebook": "1.0.0-beta7",
"Microsoft.AspNet.Authentication.Google": "1.0.0-beta7",
"Microsoft.AspNet.Authentication.MicrosoftAccount": "1.0.0-beta7",
"Microsoft.AspNet.Authentication.Twitter": "1.0.0-beta7",
"Microsoft.AspNet.Diagnostics": "1.0.0-beta7",
"Microsoft.AspNet.Diagnostics.Entity": "7.0.0-beta7",
"Microsoft.AspNet.Identity.EntityFramework": "3.0.0-beta7",
"Microsoft.AspNet.Server.IIS": "1.0.0-beta7",
"Microsoft.AspNet.Server.WebListener": "1.0.0-beta7",
"Microsoft.AspNet.StaticFiles": "1.0.0-beta7",
"Microsoft.AspNet.Tooling.Razor": "1.0.0-beta7",
"Microsoft.Framework.Configuration.Abstractions": "1.0.0-beta7",
"Microsoft.Framework.Configuration.Json": "1.0.0-beta7",
"Microsoft.Framework.Configuration.UserSecrets": "1.0.0-beta7",
"Microsoft.Framework.Logging": "1.0.0-beta7",
"Microsoft.Framework.Logging.Console": "1.0.0-beta7",
"Microsoft.VisualStudio.Web.BrowserLink.Loader": "14.0.0-beta7",
"RazorEngine": "4.2.2-beta1"
},
...
"frameworks": {
"dnx451": { }
},
...
我的模板是:
@model dynamic
@{
Layout = null;
}
<!DOCTYPE html>
<html lang="en" xmlns="http://www.w3.org/1999/xhtml">
<head>
<meta charset="utf-8" />
<title>Registration</title>
</head>
<body>
<p>
Hello, @Model
</p>
</body>
</html>有没有人有类似的问题？还有另一种解析MVC 6模板的方法吗？
amd*_*amd 26
在以下版本中正常工作1.0.0,RC2
谁的目标是aspnetcore RC2,这个代码片段可能对您有所帮助:
Startup课堂上的 IoC容器中注册此服务https://gist.github.com/ahmad-moussawi/1643d703c11699a6a4046e57247b4d09
// using a Model
string html = view.Render("Emails/Test", new Product("Apple"));
// using a Dictionary<string, object>
var viewData = new Dictionary<string, object>();
viewData["Name"] = "123456";
string html = view.Render("Emails/Test", viewData);
Razor中的链接呈现为相对 URL,因此这不适用于外部视图(如电子邮件等).
至于现在我在控制器上生成链接并通过ViewModel将其传递给视图.
源代码摘自(感谢@pholly):https://github.com/aspnet/Entropy/blob/dev/samples/Mvc.RenderViewToString/RazorViewToStringRenderer.cs)
pho*_*lly 19
我找到了这个讨论它的线程:https://github.com/aspnet/Mvc/issues/3091
线程中有人在这里创建了一个示例服务:https://github.com/aspnet/Entropy/blob/dev/samples/Mvc.RenderViewToString/RazorViewToStringRenderer.cs
经过反复试验后,我能够减少服务,因此它只需要一个有效的HttpContext和一个,ViewEngine并且我添加了一个不需要模型的重载.视图与应用程序根目录相关(它们不必存在于Views文件夹中).
您需要注册该服务Startup.cs并注册HttpContextAccessor:
//Startup.cs ConfigureServices()
services.AddTransient<ViewRenderService>();
services.AddSingleton<IHttpContextAccessor, HttpContextAccessor>();
using Microsoft.AspNetCore.Http;
using Microsoft.AspNetCore.Mvc;
using Microsoft.AspNetCore.Mvc.ModelBinding;
using Microsoft.AspNetCore.Mvc.Razor;
using Microsoft.AspNetCore.Mvc.Rendering;
using Microsoft.AspNetCore.Mvc.ViewFeatures;
using System;
using System.IO;
namespace LibraryApi.Services
{
public class ViewRenderService
{
IRazorViewEngine _viewEngine;
IHttpContextAccessor _httpContextAccessor;
public ViewRenderService(IRazorViewEngine viewEngine, IHttpContextAccessor httpContextAccessor)
{
_viewEngine = viewEngine;
_httpContextAccessor = httpContextAccessor;
}
public string Render(string viewPath)
{
return Render(viewPath, string.Empty);
}
public string Render<TModel>(string viewPath, TModel model)
{
var viewEngineResult = _viewEngine.GetView("~/", viewPath, false);
if (!viewEngineResult.Success)
{
throw new InvalidOperationException($"Couldn't find view {viewPath}");
}
var view = viewEngineResult.View;
using (var output = new StringWriter())
{
var viewContext = new ViewContext();
viewContext.HttpContext = _httpContextAccessor.HttpContext;
viewContext.ViewData = new ViewDataDictionary<TModel>(new EmptyModelMetadataProvider(), new ModelStateDictionary())
{ Model = model };
viewContext.Writer = output;
view.RenderAsync(viewContext).GetAwaiter().GetResult();
return output.ToString();
}
}
}
}
用法示例:
using Microsoft.AspNetCore.Mvc;
using Microsoft.Extensions.Logging;
using LibraryApi.Services;
using System.Dynamic;
namespace LibraryApi.Controllers
{
[Route("api/[controller]")]
public class ValuesController : Controller
{
ILogger<ValuesController> _logger;
ViewRenderService _viewRender;
public ValuesController(ILogger<ValuesController> logger, ViewRenderService viewRender)
{
_logger = logger;
_viewRender = viewRender;
}
// GET api/values
[HttpGet]
public string Get()
{
//ViewModel is of type dynamic - just for testing
dynamic x = new ExpandoObject();
x.Test = "Yes";
var viewWithViewModel = _viewRender.Render("eNotify/Confirm.cshtml", x);
var viewWithoutViewModel = _viewRender.Render("MyFeature/Test.cshtml");
return viewWithViewModel + viewWithoutViewModel;
}
}
}
Vli*_*nce 15
在过去,我使用RazorEngine了类库中的内部,因为我的目标是从此类库中呈现模板.
根据我的理解,你似乎是在一个MVC 6.0项目中,所以为什么不使用一个RenderPartialViewToString()方法而不必添加依赖RazorEngine？
请记住,我只是在问,因为我很好奇.
例如,在VS2015中,我创建了一个新的ASP.NET Web应用程序,并从ASP.NET 5预览模板中选择了Web应用程序模板.
在ViewModels文件夹里面,我创建了一个PersonViewModel:
public class PersonViewModel
{
public string FirstName { get; set; }
public string LastName { get; set; }
public string FullName
{
get
{
return string.Format("{0} {1}", this.FirstName, this.LastName);
}
}
}
然后我创建了一个新的BaseController并添加了一个RenderPartialViewToString()方法:
public string RenderPartialViewToString(string viewName, object model)
{
if (string.IsNullOrEmpty(viewName))
viewName = ActionContext.ActionDescriptor.Name;
ViewData.Model = model;
using (StringWriter sw = new StringWriter())
{
var engine = Resolver.GetService(typeof(ICompositeViewEngine)) as ICompositeViewEngine;
ViewEngineResult viewResult = engine.FindPartialView(ActionContext, viewName);
ViewContext viewContext = new ViewContext(ActionContext, viewResult.View, ViewData, TempData, sw,new HtmlHelperOptions());
var t = viewResult.View.RenderAsync(viewContext);
t.Wait();
return sw.GetStringBuilder().ToString();
}
}
感谢@DavidG的方法
在Views-->Shared文件夹中,我创建了一个新的Templates文件夹,其中我添加了一个简单的RegistrationTemplate.cshtmlView 强类型到我PersonViewModel这样:
@model MyWebProject.ViewModels.PersonViewModel
<!DOCTYPE html>
<html lang="en" xmlns="http://www.w3.org/1999/xhtml">
<head>
<meta charset="utf-8" />
<title>Registration</title>
</head>
<body>
<p>
Hello, @Model.FullName
</p>
</body>
</html>
最后一步是让我Controller继承我的BaseController
public class MyController : BaseController
并创建类似于:
public IActionResult Index()
{
var model = new PersonViewModel();
model.FirstName = "Frank";
model.LastName = "Underwood";
var emailbody = base.RenderPartialViewToString("Templates/RegistrationTemplate", model);
return View();
}
当然,上面的例子是无用的,因为我对变量什么都不做,emailbody但想法是显示它是如何使用的.
在这一点上,我可以(例如),调用EmailService并传递emailbody:
_emailService.SendEmailAsync("test@test.com", "registration", emailbody);
我不确定这是否适合您当前的任务.
Tod*_*ams 12
今天我已经完成了我的图书馆,可以解决你的问题.您可以在ASP.NET中使用它,因为它没有依赖它
例:
string content = "Hello @Model.Name. Welcome to @Model.Title repository";
var model = new
{
Name = "John Doe",
Title = "RazorLight"
};
var engine = new RazorLightEngine();
string result = engine.ParseString(content, model);
//Output: Hello John Doe, Welcome to RazorLight repository
更多:https://github.com/toddams/RazorLight
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