向列表R中的每个子列表添加向量

Question

我有两个具有相同结构的列表.我想将它们组合起来以产生以下所需的输出.

A <- list(c(1,2,3,2,1,4),c(7,3,1,2,2,1),c(2,3,7,2,2,8))
B <- list(c(2,1,3,2),c(3,1,5,2),c(2,4,5,1))

# Desired Output

[[1]]
    [1] 1 2 3 2 1 4
    [1] 2 1 3 2
[[2]]
    [1] 7 3 1 2 2 1
    [1] 3 1 5 2
[[3]]
    [1] 2 3 7 2 2 8
    [1] 2 4 5 1

# I have tried with the items beloww and nothing works as to produce the shown desired output. Would you happen to know on how to combine the two vectors as to produce the outcome below. 

c
cbind(A,B)
     A         B        
[1,] Numeric,6 Numeric,4
[2,] Numeric,6 Numeric,4
[3,] Numeric,6 Numeric,4

merge
append

Answer 1

由于list"A"和"B"中相应元素的长度不同,我们可以将其保持为a list.一个方便的功能是Map在list'A'和'B'的相应元素上执行此操作.

lst <- Map(list, A, B)

如果我们要保持这个作为一个matrix与NA垫的长度不等,一种选择是stri_list2matrix从library(stringi).输出将是a matrix,但我们需要将character输出转换回来numeric

library(stringi)
lst1 <- lapply(lst, stri_list2matrix, byrow=TRUE)
lapply(lst1, function(x) matrix(as.numeric(x),nrow=2))
#[[1]]
#      [,1] [,2] [,3] [,4] [,5] [,6]
#[1,]    1    2    3    2    1    4
#[2,]    2    1    3    2   NA   NA

#[[2]]
#     [,1] [,2] [,3] [,4] [,5] [,6]
#[1,]    7    3    1    2    2    1
#[2,]    3    1    5    2   NA   NA

#[[3]]
#     [,1] [,2] [,3] [,4] [,5] [,6]
#[1,]    2    3    7    2    2    8
#[2,]    2    4    5    1   NA   NA