以编程方式获取当前页面

Question

在JSF支持Bean(Managed Bean的,虚焊豆,无所谓),我可以得到上下文路径的客户端是通过调用

FacesContext ctx = FacesContext.getCurrentInstance();
String path = ctx.getExternalContext().getRequestContextPath();

这给了我客户端当前访问的路径,比如/myapplication.是否也可以得到当前页面,就像/home.faces,怎么样？

Answer 1

You normally want to use UIViewRoot#getViewId() for this.

String viewId = facesContext.getViewRoot().getViewId();

This is in EL also available as follows:

#{view.viewId}

Exactly this value is reuseable in navigation case outcomes such as <h:link outcome> and <h:button outcome>.

或者,您也可以使用HttpServletRequest#getRequestURI()获取最终用户在浏览器地址栏中实际看到的内容.

String uri = ((HttpServletRequest) externalContext.getRequest()).getRequestURI();

EL中的哪个也可用如下:

#{request.requestURI}

确切地说,这个值可以在<h:outputLink value>或简单地重复使用<a href>.请注意,您不能将其用作导航案例结果.

Answer 2

好的,明白了,就是这样

FacesContext ctx = FacesContext.getCurrentInstance();
HttpServletRequest servletRequest = (HttpServletRequest) ctx.getExternalContext().getRequest();
// returns something like "/myapplication/home.faces"
String fullURI = servletRequest.getRequestURI();