使用FOSRestBundle REST API设置注册FOSUserBundle

Question

问题已解决,请检查我的答案.

我正在我的Symfony2.7 rest api上建立一个注册端点.我正在使用FosRestBundle和FosUserBundle

这是用户模型:

<?php

namespace AppBundle\Entity;

use FOS\UserBundle\Model\User as BaseUser;
use Doctrine\ORM\Mapping as ORM;

/**
 * @ORM\Entity
 * @ORM\Table(name="fos_user")
 */
class User extends BaseUser {

    /**
     * @ORM\Id
     * @ORM\Column(type="integer")
     * @ORM\GeneratedValue(strategy="AUTO")
     */
    protected $id;






    public function __construct() {
        parent::__construct();
        // your own logic
    }

}

\ 这是UserType表单: \

class UserType extends AbstractType
{
    /**
     * @param FormBuilderInterface $builder
     * @param array $options
     */
    public function buildForm(FormBuilderInterface $builder, array $options)
    {
        $builder
            ->add('email', 'email')
            ->add('username', null)
            ->add('plainPassword', 'repeated', array(
                'type' => 'password',

                'first_options' => array('label' => 'password'),
                'second_options' => array('label' => 'password_confirmation'),

            ))
        ;
    }

    /**
     * @param OptionsResolverInterface $resolver
     */
    public function setDefaultOptions(OptionsResolverInterface $resolver)
    {
        $resolver->setDefaults(array(
            'data_class' => 'AppBundle\Entity\User',
            'csrf_protection'   => false,
        ));
    }

    /**
     * @return string
     */
    public function getName()
    {
        return 'user';
    }
}

而这个帖子用户控制器:

public function postUserAction(\Symfony\Component\HttpFoundation\Request $request) {
        $user = new \AppBundle\Entity\User();
        $form = $this->createForm(new \AppBundle\Form\UserType(), $user);
        $form->handleRequest($request);

        if ($form->isValid()) {
            $em = $this->getDoctrine()->getManager();
            $em->persist($user);
            $em->flush();


            $view = $this->view(array('token'=>$this->get("lexik_jwt_authentication.jwt_manager")->create($user)), Codes::HTTP_CREATED);

            return $this->handleView($view);

        }

        return array(
            'form' => $form,
        );
    }

问题是,当我提交错误的信息或空信息时,服务器返回一个错误的格式化500错误,其中带有错误格式化条目列表的json响应状态中非空行的空值的doctrine/mysql详细信息.

有关如何解决此问题的任何想法？为什么验证得到通过和

Answer 1

好好花了很多时间阅读FOSUserBundle代码,特别是注册控制器和表格工厂,我想出了一个完全可行的解决方案.

在做任何事情之前,不要忘记在symfony2配置中禁用CSRF.

这是我用来注册的控制器:

 public function postUserAction(\Symfony\Component\HttpFoundation\Request $request) {


        /** @var $formFactory \FOS\UserBundle\Form\Factory\FactoryInterface */
        $formFactory = $this->get('fos_user.registration.form.factory');
        /** @var $userManager \FOS\UserBundle\Model\UserManagerInterface */
        $userManager = $this->get('fos_user.user_manager');
        /** @var $dispatcher \Symfony\Component\EventDispatcher\EventDispatcherInterface */
        $dispatcher = $this->get('event_dispatcher');

        $user = $userManager->createUser();
        $user->setEnabled(true);

        $event = new \FOS\UserBundle\Event\GetResponseUserEvent($user, $request);
        $dispatcher->dispatch(\FOS\UserBundle\FOSUserEvents::REGISTRATION_INITIALIZE, $event);

        if (null !== $event->getResponse()) {
            return $event->getResponse();
        }

        $form = $formFactory->createForm();
        $form->setData($user);

        $form->handleRequest($request);

        if ($form->isValid()) {
            $event = new \FOS\UserBundle\Event\FormEvent($form, $request);
            $dispatcher->dispatch(\FOS\UserBundle\FOSUserEvents::REGISTRATION_SUCCESS, $event);

            $userManager->updateUser($user);

            if (null === $response = $event->getResponse()) {
                $url = $this->generateUrl('fos_user_registration_confirmed');
                $response = new \Symfony\Component\HttpFoundation\RedirectResponse($url);
            }

            $dispatcher->dispatch(\FOS\UserBundle\FOSUserEvents::REGISTRATION_COMPLETED, new \FOS\UserBundle\Event\FilterUserResponseEvent($user, $request, $response));

            $view = $this->view(array('token' => $this->get("lexik_jwt_authentication.jwt_manager")->create($user)), Codes::HTTP_CREATED);

            return $this->handleView($view);
        }

        $view = $this->view($form, Codes::HTTP_BAD_REQUEST);
        return $this->handleView($view);
    }

现在棘手的部分是使用REST提交表单.问题是,当我发送像这样的JSON时:

{
        "email":"xxxxx@xxxx.com",
        "username":"xxx",
        "plainPassword":{
            "first":"xxx",
            "second":"xxx"
        }
    }

API没有提交任何内容就响应了.

解决方案是Symfony2正在等待您将表单数据封装在表单名称中!

问题是"我没有创建这种形式所以我不知道它的名字是什么......".所以我再次使用捆绑代码,发现表单类型为fos_user_registration,getName函数返回fos_user_registration_form.

结果我尝试以这种方式提交我的JSON:

{"fos_user_registration_form":{
        "email":"xxxxxx@xxxxxxx.com",
        "username":"xxxxxx",
        "plainPassword":{
            "first":"xxxxx",
            "second":"xxxxx"
        }
    }}

瞧!有效.如果你正在努力设置你的fosuserbundle与fosrestbundle和LexikJWTAuthenticationBundle只是问我,我会很乐意提供帮助.