我试图通过返回选择查询将多个值插入到特定的表中我无法插入到表中.如果我在某处做错了请告诉我.谢谢提前.
create or replace PROCEDURE DE_DUP_PROC1 (Dy_File_Name IN VARCHAR2,
SUPPLIER_CD IN VARCHAR2,
EXT_PHARMA_ID IN VARCHAR2,
FLAG_VALUE IN VARCHAR2,
ERR_COUNT IN VARCHAR2,
OUTPUT_STATUS OUT NUMBER)
AS
c2 SYS_REFCURSOR;
De_Dub_rec1 VARCHAR2 (2000);
v_sql VARCHAR2 (2000);
v_sql1 VARCHAR2 (2000);
ORGNIZATION_ID NUMBER(20);
PHARMACY_ID NUMBER(38);
v_dup_count VARCHAR2 (2000);
SRC_ID NUMBER(38);
DE_DUP_COUNT NUMBER(38);
DE_REC_COUNT1 NUMBER(10) := 3;
TYPE rec_typ IS RECORD
(
OLD_TRANS_GUID VARCHAR2 (255),
R_DSPNSD_DT DATE,
DETL_CLMNS_HASH1 VARCHAR2(255),
KEY_CLMNS_HASH1 VARCHAR2(255),
SUPPLIER_PHARMACY_CD1 VARCHAR2(200)
);
De_Dub_rec rec_typ;
BEGIN
IF DE_REC_COUNT1 > 0
THEN
OUTPUT_STATUS := 0;
dbms_output.put_line(OUTPUT_STATUS);
ELSE
SRC_ID := SRC_FILE_ID_SEQ.nextval
OPEN c2 FOR
( ' SELECT S.TRANS_GUID AS OLD_TRANS_GUID,S.DETL_CLMNS_HASH AS DETL_CLMNS_HASH1 ,S.KEY_CLMNS_HASH AS KEY_CLMNS_HASH1,S.RX_DSPNSD_DT AS R_DSPNSD_DT,
S.SUPPLIER_PHARMACY_CD AS SUPPLIER_PHARMACY_CD1 FROM (SELECT stg.*, row_number() over (partition BY key_clmns_hash ORDER BY 1) AS RN FROM
' || Dy_File_Name || ' stg ) s JOIN ps_pharmacy p ON s.extrnl_pharmacy_id = p.extrnl_pharmacy_id LEFT JOIN ps_rx_hist H
ON h.key_clmns_hash = s.key_clmnS_hash
AND h.rx_dspnsd_dt = s.rx_dspnsd_dt
AND s.supplier_pharmacy_cd = h.SUPPLIER_PHARMACY_CD
WHERE S.RN > 1
OR s.detl_clmns_hash = h.detl_clmns_hash ' );
LOOP
FETCH c2 INTO De_Dub_rec;
EXIT WHEN c2%NOTFOUND;
insert into PS_RX_DUPES(TRANS_GUID,DETL_CLMNS_HASH,KEY_CLMNS_HASH,RX_DSPNSD_DT,SUPPLIER_PHARMACY_CD,SRC_FILE_ID)
values(De_Dub_rec.OLD_TRANS_GUID,De_Dub_rec.DETL_CLMNS_HASH1,De_Dub_rec.KEY_CLMNS_HASH1,De_Dub_rec.R_DSPNSD_DT,De_Dub_rec.SUPPLIER_PHARMACY_CD1,SRC_ID);
commit;
END LOOP;
OUTPUT_STATUS := 1;
dbms_output.put_line(OUTPUT_STATUS);
END IF;
END DE_DUP_PROC1;
Run Code Online (Sandbox Code Playgroud)
每当我执行上面的存储过程时我都会出现错误
declare
OUTPUT_STATUS number(2);
begin
DE_DUP_PROC1('T_MCL_10622_20150317_01526556','MCL','10622','BD','3',OUTPUT_STATUS);
end;
Error at line 1
- ORA-01007: variable not in select list
ORA-06512: at "PS_ADMIN.DE_DUP_PROC1", line 53
ORA-06512: at line 6
Run Code Online (Sandbox Code Playgroud)
ORA-01007当我们的查询列与目标变量不匹配时,Oracle会抛出.
第53行是这一行FETCH c2 INTO De_Dub_rec;,所以线索是光标的投影与记录类型不匹配.
你的自由文本SELECT语句杂乱无章,这使调试变得困难.让我们整理一下预测:
SELECT S.TRANS_GUID AS OLD_TRANS_GUID
, S.DETL_CLMNS_HASH AS DETL_CLMNS_HASH1
, S.KEY_CLMNS_HASH AS KEY_CLMNS_HASH1
, S.RX_DSPNSD_DT AS R_DSPNSD_DT
, S.SUPPLIER_PHARMACY_CD AS SUPPLIER_PHARMACY_CD1
FROM ...
Run Code Online (Sandbox Code Playgroud)
现在很容易看到列顺序与类型的属性顺序不同:
TYPE rec_typ IS RECORD
(
OLD_TRANS_GUID VARCHAR2 (255),
R_DSPNSD_DT DATE,
DETL_CLMNS_HASH1 VARCHAR2(255),
KEY_CLMNS_HASH1 VARCHAR2(255),
SUPPLIER_PHARMACY_CD1 VARCHAR2(200)
);
Run Code Online (Sandbox Code Playgroud)
所以你的代码试图将一个字符串放入一个日期变量(反之亦然,但至少Oracle可以强制转换它).
所有这些都证明清晰的布局不是一个愚蠢的强迫症.编写代码时的规则可以通过突出显示明显的错误来帮助我们更快地编写更好的代码.