我有一个包含(记录格式)json 字符串的数据框,如下所示:
In[9]: pd.DataFrame( {'col1': ['A','B'], 'col2': ['[{"t":"05:15","v":"20.0"}, {"t":"05:20","v":"25.0"}]',
'[{"t":"05:15","v":"10.0"}, {"t":"05:20","v":"15.0"}]']})
Out[9]:
col1 col2
0 A [{"t":"05:15","v":"20.0"}, {"t":"05:20","v":"2...
1 B [{"t":"05:15","v":"10.0"}, {"t":"05:20","v":"1...
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我想提取 json 并为每条记录向数据帧添加一个新行:
co1 t v
0 A 05:15:00 20
1 A 05:20:00 25
2 B 05:15:00 10
3 B 05:20:00 15
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我一直在试验以下代码:
def json_to_df(x):
df2 = pd.read_json(x.col2)
return df2
df.apply(json_to_df, axis=1)
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但结果数据帧被分配为元组,而不是创建新行。有什么建议吗?
问题apply在于您需要返回多行,而它只需要一行。一个可能的解决方案:
def json_to_df(row):
_, row = row
df_json = pd.read_json(row.col2)
col1 = pd.Series([row.col1]*len(df_json), name='col1')
return pd.concat([col1,df_json],axis=1)
df = map(json_to_df, df.iterrows()) #returns a list of dataframes
df = reduce(lambda x,y:x.append(y), x) #glues them together
df
col1 t v
0 A 05:15 20
1 A 05:20 25
0 B 05:15 10
1 B 05:20 15
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