Ian*_*oyd 11 .net active-directory
如何在Active Directory中查找用户?
一些示例用户名是:
重要的是要注意我不知道域的名称,我不应该硬编码.
using System.DirectoryServices;
/// <summary>
/// Gets the email address, if defined, of a user from Active Directory.
/// </summary>
/// <param name="userid">The userid of the user in question. Make
/// sure the domain has been stripped first!</param>
/// <returns>A string containing the user's email address, or null
/// if one was not defined or found.</returns>
public static string GetEmail(string userid)
{
DirectorySearcher searcher;
SearchResult result;
string email;
// Check first if there is a slash in the userid
// If there is, domain has not been stripped
if (!userid.Contains("\\"))
{
searcher = new DirectorySearcher();
searcher.Filter = String.Format("(SAMAccountName={0})", userid);
searcher.PropertiesToLoad.Add("mail");
result = searcher.FindOne();
if (result != null)
{
email = result.Properties["mail"][0].ToString();
}
}
return email;
}
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它特别确保您没有传递完整的用户名.例如
Bad: avatopia\ian
Bad: avatar\ian
Good: ian
Good: ian
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由于您不允许通过域,因此无法区分这两个用户
ian
ian
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另一个人在sackoverflow上有同样的问题,但接受的答案说你必须
首先找到所需域的命名上下文
我不知道 "命名上下文"是什么,我不知道"必需的域名"是什么.我真的不想写一个正则表达式来尝试将用户名解析为域名和帐户名,例如
domain.something\user-name
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成
domain.something
user-name
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因为我知道会有一些边缘情况我会出错.我想要在Active Directory中查找用户的正确,有意的方法.
CodeProject上有一个很好的页面如何在Active Directory中执行几乎所有操作,但是您无法通过用户名查找用户的信息
我希望我可以给我的域控制器(无论是谁,无论它在哪里,无论它叫什么)一个用户名,它将找出用户所属的域,与该域控制器通信,并完成工作.
这适合我.
您应该能够区分不同域控制器上的不同用户(即域/用户名),因为ldappaths会有所不同.根据你的意思,你不在乎,因为你没有指定ldappath.
您正在就剥离User.Identity.Name的域名进行出价交易.但是我不确定你担心的是什么,你只需要把弦切成两半,第一次遇到'\'时就要砍掉了.
如果您不喜欢,可以使用"正确的方法":http://msdn.microsoft.com/en-us/library/ms973834.aspx
这也很好 http://geekswithblogs.net/mhamilton/archive/2005/09/30/55621.aspx
/// This is some imaginary code to show you how to use it
Session["USER"] = User.Identity.Name.ToString();
Session["LOGIN"] = RemoveDomainPrefix(User.Identity.Name.ToString()); // not a real function :D
string ldappath = "LDAP://your_ldap_path";
// "LDAP://CN=<group name>, CN =<Users>, DC=<domain component>, DC=<domain component>,..."
Session["cn"] = GetAttribute(ldappath, (string)Session["LOGIN"], "cn");
Session["displayName"] = GetAttribute(ldappath, (string)Session["LOGIN"], "displayName");
Session["mail"] = GetAttribute(ldappath, (string)Session["LOGIN"], "mail");
Session["givenName"] = GetAttribute(ldappath, (string)Session["LOGIN"], "givenName");
Session["sn"] = GetAttribute(ldappath, (string)Session["LOGIN"], "sn");
/// working code
public static string GetAttribute(string ldappath, string sAMAccountName, string attribute)
{
string OUT = string.Empty;
try
{
DirectoryEntry de = new DirectoryEntry(ldappath);
DirectorySearcher ds = new DirectorySearcher(de);
ds.Filter = "(&(objectClass=user)(objectCategory=person)(sAMAccountName=" + sAMAccountName + "))";
SearchResultCollection results = ds.FindAll();
foreach (SearchResult result in ds.FindAll())
{
OUT = GetProperty(result, attribute);
}
}
catch (Exception t)
{
// System.Diagnostics.Debug.WriteLine(t.Message);
}
return (OUT != null) ? OUT : string.Empty;
}
public static string GetProperty(SearchResult searchResult, string PropertyName)
{
if (searchResult.Properties.Contains(PropertyName))
{
return searchResult.Properties[PropertyName][0].ToString();
}
else
{
return string.Empty;
}
}
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对于域/用户名
public static string GetDomain(string s)
{
int stop = s.IndexOf("\\");
return (stop > -1) ? s.Substring(0, stop + 1) : null;
}
public static string GetLogin(string s)
{
int stop = s.IndexOf("\\");
return (stop > -1) ? s.Substring(stop + 1, s.Length - stop - 1) : null;
}
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对于username @ domain style
public static string GetDomain(string s) //untested
{
int stop = s.IndexOf("@");
return (stop > -1) ? s.Substring(stop + 1, s.Length - stop - 1) : null;
}
public static string GetLogin(string s) //untested
{
int stop = s.IndexOf("@");
return (stop > -1) ? s.Substring(0, stop) : null;
}
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