cha*_*lor 4 mysql sql postgresql
我用google搜索和stackoverflowed高低,并没有找到任何具体的解决方案来显示每组的第二(第n)记录.
请考虑下表(按created_at desc排序):
----------------------------------------------
bid_id | status | created_at
----------------------------------------------
1 | cancelled | 2015-10-03
1 | awarded | 2015-10-02
1 | pending | 2015-10-01
2 | pending | 2015-10-01
3 | denied | 2015-10-02
3 | pending | 2015-10-01
Run Code Online (Sandbox Code Playgroud)
结果输出应如下所示(按bid_id分组):
bid_id | status | created_at
----------------------------------------------
1 | awarded | 2014-10-02
3 | pending | 2014-10-01
Run Code Online (Sandbox Code Playgroud)
什么是有效的SQL来实现这一目标?任何提示都非常感谢!
您可以使用row_number在bi_id按created_at列排序的每个分区中分配行号.然后,您只需选择第二行或您需要的行.这适用于postgres它支持window功能.
select bid_id, status, created_at
from
(
select bid_id, status, created_at,
row_number() over(partition by bid_id order by created_at desc) as rn
from tablename
) x
where x.rn = 2;
Run Code Online (Sandbox Code Playgroud)
| 归档时间: |
|
| 查看次数: |
2024 次 |
| 最近记录: |