我有一对多的关系:
class GameSystem: Object {
dynamic var gameSystemName = ""
}
class games: Object {
dynamic var gameSystemName = gameSystemName().name
dynamic var gameTitle = ""
dynamic var gameGenre = ""
}
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该gameSystemNames的当前显示上的TableView.如果用户删除了a gameSystemName,我希望删除gameSystemName所有该系统的游戏.
我目前使用的代码只会删除GameSystem,但会保留所有游戏.
func deleteRowAtIndexPath(indexPath: NSIndexPath) {
let realm = Realm()
let objectToDelete = gameSystems[indexPath.row]
realm.write {
realm.delete(objectToDelete)
}
gameSystemTableView.deleteRowsAtIndexPaths([indexPath], withRowAnimation: .Fade)
gameSystems = Realm(path: Realm.defaultPath).objects(GameSystem)
}
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我假设有一个简单的方法来做到这一点.
如果保持模型不变,解决方案是首先查询关系的相关对象Game:
// …
let objectToDelete = gameSystems[indexPath.row]
let gameSystemName = objectToDelete.gameSystemName
realm.write {
let games = realm.objects(Game).filter("gameSystemName = ?", gameSystemName)
realm.delete(games)
realm.delete(objectToDelete)
}
// …
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我建议你添加一个显式链接到你的模型,而不是通过松散链接的外键表达关系.但是对象映射非常个性化,并且可能依赖于超出问题范围和此答案的进一步约束.如需进一步参考,如下所示:
class GameSystem : Object {
dynamic var name = ""
let games = List<Game>()
}
class Game : Object {
dynamic var title = ""
dynamic var genre = ""
// Use a backlink
// (https://realm.io/docs/swift/latest/#inverse-relationships)
dynamic var gameSystem: GameSystem? {
return linkingObjects(GameSystem.self, forProperty: "games").first
}
}
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如果你设置这样的模型,你可以很容易地删除你的游戏:
// …
let objectToDelete = gameSystems[indexPath.row]
realm.write {
realm.delete(objectToDelete.games)
realm.delete(objectToDelete)
}
// …
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注意:将来,Realm会将Cascading Deletes作为功能.一旦发布,您甚至不需要处理相关游戏的手动删除,但您宁愿能够在模型中声明强关系,以便自动删除游戏.
您也可以反过来声明您的链接,但这将使得将来可能更难使用像Cascading Deletes这样的功能.但是,现在删除它们的代码看起来与上面相同.
class GameSystem : Object {
dynamic var name = ""
// Use a backlink
// (https://realm.io/docs/swift/latest/#inverse-relationships)
dynamic var games: [Game] {
return linkingObjects(Game.self, forProperty: "gameSystem")
}
}
class Game : Object {
dynamic var title = ""
dynamic var genre = ""
let gameSystem: GameSystem? = nil
}
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