lea*_*sql 2 sql oracle outer-join
作品:
AND UPPER(a.name) = b.lname(+)
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不起作用
AND UPPER(a.name) = UPPER(b.lname) (+)
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转移到ANSI连接是一个选项,但是一个艰难的选择.这个代码应该在很多地方改变,并且有很多连接.我希望这个语法正确并且在我的路上.
可能吗?
除了Yuckiness之外,将UPPER()与旧的skool OUTER JOIN语法相结合本身就是简单的:我们只需要按正确的顺序获取括号:
SQL> select t23.name
2 , d.university
3 from t23
4 , t_doctors d
5 where upper(t23.name) = upper(d.name(+))
6 order by t23.id
7 /
NAME UNIVERSITY
------------ --------------------
SAM-I-AM
MR KNOX
FOX IN SOCKS
CAT
LORAX
BILLY
MAISIE
DR SINATRA Whoville U
DR FONZ U of Grin-itch
PINNER BLINN
10 rows selected.
SQL>
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以下是如何使用多个表部署更新的语法:
SQL> select t23.name
2 , d.university
3 , k.school
4 from t23
5 left outer join t_doctors d
6 on upper(t23.name) = upper(d.name)
7 left outer join t_kids k
8 on upper(t23.name) = upper(k.name)
9 order by t23.id
10 /
NAME UNIVERSITY SCHOOL
------------ -------------------- --------------------
SAM-I-AM Mulberry St Junior
MR KNOX
FOX IN SOCKS
CAT
LORAX
BILLY Roover River High
MAISIE Roover River High
DR SINATRA Whoville U
DR FONZ U of Grin-itch
PINNER BLINN
10 rows selected.
SQL>
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