Oracle外连接与上层短手

lea*_*sql 2 sql oracle outer-join

作品:

AND UPPER(a.name) = b.lname(+)
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不起作用

AND UPPER(a.name) = UPPER(b.lname) (+)
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转移到ANSI连接是一个选项,但是一个艰难的选择.这个代码应该在很多地方改变,并且有很多连接.我希望这个语法正确并且在我的路上.

可能吗?

APC*_*APC 8

除了Yuckiness之外,将UPPER()与旧的skool OUTER JOIN语法相结合本身就是简单的:我们只需要按正确的顺序获取括号:

SQL> select t23.name
  2         , d.university
  3  from t23
  4       , t_doctors d
  5  where upper(t23.name) = upper(d.name(+))
  6  order by t23.id
  7  /

NAME         UNIVERSITY
------------ --------------------
SAM-I-AM
MR KNOX
FOX IN SOCKS
CAT
LORAX
BILLY
MAISIE
DR SINATRA   Whoville U
DR FONZ      U of Grin-itch
PINNER BLINN

10 rows selected.

SQL> 
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以下是如何使用多个表部署更新的语法:

SQL> select t23.name
  2         , d.university
  3         , k.school
  4  from t23
  5       left outer join t_doctors d
  6                  on upper(t23.name) = upper(d.name)
  7       left outer join t_kids k
  8                  on upper(t23.name) = upper(k.name)
  9  order by t23.id
 10  /

NAME         UNIVERSITY           SCHOOL
------------ -------------------- --------------------
SAM-I-AM                          Mulberry St Junior
MR KNOX
FOX IN SOCKS
CAT
LORAX
BILLY                             Roover River High
MAISIE                            Roover River High
DR SINATRA   Whoville U
DR FONZ      U of Grin-itch
PINNER BLINN

10 rows selected.

SQL>
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  • +1:有趣,我希望我永远不必记住这个窍门:) (2认同)