use*_*678 5 python file watchdog
我想知道如何检查文件夹下特定文件的更改。我发现看门狗模块可以检查文件夹中文件的更改,但我只需要 1 个文件(具有固定名称)。
请对此提供帮助,谢谢。
class MyHandler(FileModifiedEvent):
def on_modified(self, event):
if __name__ == "__main__":
integrity_file_path = DATASTORE_DIRECTORY_PATH + '/schedule.xml'
event_handler = MyHandler()
observer = Observer()
observer.schedule(MyHandler(), path=integrity_file_path,recursive=True)
observer.start()
try:
while True:
time.sleep(5)
except KeyboardInterrupt:
observer.stop()
observer.join()
Run Code Online (Sandbox Code Playgroud)
您可以将watchdog.events.PatternMatchingEventHandler事件处理程序子类化并修改它以在事件发生时执行您想要的任何操作。您可以将模式设置为要监视的文件名。
然而,这个有点棘手。在幕后,它使用pathtools.patterns进行模式匹配。它还将目录附加到要匹配的模式。这意味着您需要将文件的完整路径作为文件名“模式”参数传递给事件处理程序。如果不这样做,模式匹配将失败,您将不会收到任何事件通知。
下面是一个例子:
import sys, os.path, time, logging
from watchdog.observers import Observer
from watchdog.events import PatternMatchingEventHandler
class MyEventHandler(PatternMatchingEventHandler):
def on_moved(self, event):
super(MyEventHandler, self).on_moved(event)
logging.info("File %s was just moved" % event.src_path)
def on_created(self, event):
super(MyEventHandler, self).on_created(event)
logging.info("File %s was just created" % event.src_path)
def on_deleted(self, event):
super(MyEventHandler, self).on_deleted(event)
logging.info("File %s was just deleted" % event.src_path)
def on_modified(self, event):
super(MyEventHandler, self).on_modified(event)
logging.info("File %s was just modified" % event.src_path)
def main(file_path=None):
logging.basicConfig(level=logging.INFO,
format='%(asctime)s - %(message)s',
datefmt='%Y-%m-%d %H:%M:%S')
watched_dir = os.path.split(file_path)[0]
print 'watched_dir = {watched_dir}'.format(watched_dir=watched_dir)
patterns = [file_path]
print 'patterns = {patterns}'.format(patterns=', '.join(patterns))
event_handler = MyEventHandler(patterns=patterns)
observer = Observer()
observer.schedule(event_handler, watched_dir, recursive=True)
observer.start()
try:
while True:
time.sleep(1)
except KeyboardInterrupt:
observer.stop()
observer.join()
if __name__ == "__main__":
if len(sys.argv) > 1:
path = sys.argv[1]
main(file_path=path.strip())
else:
sys.exit(1)
Run Code Online (Sandbox Code Playgroud)
执行看门狗python脚本(修改文件前):
(stackoverflow)[root@joeyoung.io stackoverflow]# python watchschedule.py /usr/local/src/stackoverflow/watchdog/schedule.xml
watched_dir = /usr/local/src/stackoverflow/watchdog
patterns = /usr/local/src/stackoverflow/watchdog/schedule.xml
Run Code Online (Sandbox Code Playgroud)
在单独的控制台中修改 schedule.xml 文件:
[root@joeyoung.io watchdog]# echo "I just modified this file" >> schedule.xml
Run Code Online (Sandbox Code Playgroud)
修改 schedule.xml 后的结果:
(stackoverflow)[root@joeyoung.io stackoverflow]# python watchschedule.py /usr/local/src/stackoverflow/watchdog/schedule.xml
watched_dir = /usr/local/src/stackoverflow/watchdog
patterns = /usr/local/src/stackoverflow/watchdog/schedule.xml
2015-08-31 19:30:31 - File /usr/local/src/stackoverflow/watchdog/schedule.xml was just modified
Run Code Online (Sandbox Code Playgroud)
小智 0
我想说你可以根据以下内容检查文件的修改时间
定义一个阈值,将当前时间与修改时间进行比较,就可以知道文件是否更新了。如果文件没有被频繁修改,这将起作用。
但无论如何,如果有人打开文件,输入一些垃圾,然后删除并保存,就会出现误报。
| 归档时间: |
|
| 查看次数: |
7589 次 |
| 最近记录: |