$ _FILES和cURL的问题

Question

我在通过cURL发送$ _FILES时遇到了一些麻烦 - 使用以下代码将文件传输好了,但是我无法获取文件的名称和类型,实际上一旦$ _FILES到达其目的地的类型存储为"application/octet-stream" - 我做错了什么!？

 $count=count($_FILES['thefile']['tmp_name']);

 for($i=0;$i<$count;$i++) {
  if(!empty($_FILES['thefile']['name'][$i])) {
   $postargs[$i] = '@'.$_FILES['thefile']['tmp_name'][$i];
  }
 }


 $header = array("Content-type: multipart/form-data");
 $ch = curl_init('http://localhost/curl/rec.php');
 curl_setopt($ch,CURLOPT_USERAGENT, "Mozilla/4.0 (compatible; MSIE 5.01; Windows NT 5.0)");  
 curl_setopt($ch,CURLOPT_RETURNTRANSFER, false); 
 curl_setopt($ch,CURLOPT_ENCODING,"");
 curl_setopt($ch,CURLOPT_HTTPHEADER,$header);
 curl_setopt($ch,CURLOPT_FOLLOWLOCATION, TRUE);
 curl_setopt($ch,CURLOPT_POST,TRUE);
 curl_setopt($ch,CURLOPT_POSTFIELDS,$postargs);
 curl_exec($ch);
 curl_close($ch)

Answer 1

你应该像这样构建$ postargs,

 $postargs = array();
 foreach ($_FILES as $param => $file) {
     $postargs[$param] = '@' . $file['tmp_name'] . ';filename=' . $file['name'] . ';type=' . $file['type'];
 }