我想将下面的JSON解析为POJO.我用杰克逊来解析json.
{
"totalSize": 4,
"done": true,
"records": [
{
"attributes": {
"type": "oppor",
"url": "/service/oppor/456"
},
"AccountId": "123",
"Id": "456",
"ProposalID": "103"
}
]
}
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在上面的JSON中,字段"totalSize","done","records"和"attributes"是已知字段.鉴于"AccountId","Id"和"ProposalID"是未知字段.在上面的JSON中,我不需要"属性"成为我的bean对象的一部分.
这里是我的JSON的等效bean类
public class Result {
private int totalSize;
private boolean done;
private List<Map<String, String>> records;
public int getTotalSize() {
return totalSize;
}
public void setTotalSize(int totalSize) {
this.totalSize = totalSize;
}
public boolean isDone() {
return done;
}
public void setDone(boolean done) {
this.done = done;
}
public List<Map<String,String>> getRecords() {
return records;
}
public void setRecords(List<Map<String, String>> records) {
this.records = records;
}
}
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因此,我刚刚使用List记录元素中有未知字段来获取bean中的结果元素.在这个Map中,我不希望字段"属性".解析时如何忽略这一点?以下是我得到的例外,因为属性不是字符串元素.
com.fasterxml.jackson.databind.JsonMappingException: Can not deserialize instance of java.lang.String out of START_OBJECT token
at [Source: [B@66fdec9; line: 1, column: 40] (through reference chain: com.sample.json.Result["records"])
at com.fasterxml.jackson.databind.JsonMappingException.from(JsonMappingException.java:164)
at com.fasterxml.jackson.databind.DeserializationContext.mappingException(DeserializationContext.java:691)
at com.fasterxml.jackson.databind.deser.std.StringDeserializer.deserialize(StringDeserializer.java:46)
at com.fasterxml.jackson.databind.deser.std.StringDeserializer.deserialize(StringDeserializer.java:11)
at com.fasterxml.jackson.databind.deser.std.MapDeserializer._readAndBindStringMap(MapDeserializer.java:430)
at com.fasterxml.jackson.databind.deser.std.MapDeserializer.deserialize(MapDeserializer.java:312)
at com.fasterxml.jackson.databind.deser.std.MapDeserializer.deserialize(MapDeserializer.java:26)
at com.fasterxml.jackson.databind.deser.std.CollectionDeserializer.deserialize(CollectionDeserializer.java:227)
at com.fasterxml.jackson.databind.deser.std.CollectionDeserializer.deserialize(CollectionDeserializer.java:204)
at com.fasterxml.jackson.databind.deser.std.CollectionDeserializer.deserialize(CollectionDeserializer.java:23)
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2015/08/29 更新:
正如你所评论的那样
我通过将 JSON 解析为映射来实现动态字段支持。忽略错误的 JSON 元素是待处理的
我建议您应该处理原始 JSONObject 以"attributes"
从中删除元素。
原始JSONObject,例如:
{
"totalSize": 4,
"done": true,
"records": [
{
"attributes": {
"type": "oppor",
"url": "/service/oppor/456"
},
"AccountId": "123",
"Id": "456",
"ProposalID": "103"
}
]
}
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处理后,新的 JSONObject 将如下所示:
{
"records": {
"AccountId": "123",
"Id": "456",
"ProposalID": "103"
},
"totalSize": 4,
"done": true
}
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使用代码如下:
JSONObject jsonObject;
try {
jsonObject = new JSONObject(jsonString1);
JSONArray jsonArray = new JSONArray(jsonObject.get("records").toString());
JSONObject jsonObject1 = jsonArray.getJSONObject(0);
jsonObject1.remove("attributes");
jsonObject.put("records", jsonObject1);
} catch (JSONException e) {
e.printStackTrace();
}
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然后,使用您自己的代码achieved dynamic field support by parsing the JSON into map
。
更新结束 2015/08/29
我建议您在这种情况下使用Gson
andtransient
像这样
String jsonString1 = "{\n" +
" \"totalSize\": 4,\n" +
" \"done\": true,\n" +
" \"records\": [\n" +
" {\n" +
" \"attributes\": {\n" +
" \"type\": \"oppor\",\n" +
" \"url\": \"/service/oppor/456\"\n" +
" },\n" +
" \"AccountId\": \"123\",\n" +
" \"Id\": \"456\",\n" +
" \"ProposalID\": \"103\"\n" +
" }\n" +
" ]\n" +
"}";
Gson gson = new Gson();
Result result1 = gson.fromJson(jsonString1, Result.class);
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您的课程,请注意transient
:
public class Result {
private int totalSize;
private boolean done;
private List<Record> records;
}
public class Record {
private transient Map<String, String> attributes;
private int AccountId;
private int Id;
private int ProposalID;
}
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你会得到结果:
P/S:我在 Android Studio 中测试过:)
更新:
String jsonString1 = "{\n" +
" \"totalSize\": 4,\n" +
" \"done\": true,\n" +
" \"records\": [\n" +
" {\n" +
" \"attributes\": {\n" +
" \"type\": \"oppor\",\n" +
" \"url\": \"/service/oppor/456\"\n" +
" },\n" +
" \"AccountId\": \"123\",\n" +
" \"Id\": \"456\",\n" +
" \"ProposalID\": \"103\"\n" +
" }\n" +
" ]\n" +
"}";
Gson gson = new Gson();
Object object = gson.fromJson(jsonString1, Object.class);
Map<String, String> stringMap = (Map<String, String>) object;
Result myResult = new Result();
Iterator entries = stringMap.entrySet().iterator();
while (entries.hasNext()) {
Map.Entry entry = (Map.Entry) entries.next();
String key = entry.getKey().toString();
String value = entry.getValue().toString();
switch (key) {
case "totalSize":
myResult.totalSize = (int) Double.parseDouble(entry.getValue().toString());
break;
case "done":
myResult.done = Boolean.valueOf(entry.getValue().toString());
break;
case "records":
try{
Object object1 = entry.getValue();
List<Object> objectList = (List<Object>) object1;
Map<String, Object> stringMap2 = (Map<String, Object>) objectList.get(0);
Map<String, String> recordMap = new HashMap<>();
Iterator entries2 = stringMap2.entrySet().iterator();
while (entries2.hasNext()) {
Map.Entry entry2 = (Map.Entry) entries2.next();
String key2 = entry2.getKey().toString();
String value2 = entry2.getValue().toString();
if (!"attributes".equals(key2)) {
recordMap.put(key2, value2);
}
entries2.remove();
}
myResult.records = recordMap;
} catch (Exception e) {
e.printStackTrace();
}
break;
}
entries.remove();
}
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课程:
public class Result {
private int totalSize;
private boolean done;
private Map<String, String> records;
}
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调试结果:
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