以编程方式将颜色指定给形状

Question

我有这样的布局:

<?xml version="1.0" encoding="utf-8"?>
<layer-list xmlns:android="http://schemas.android.com/apk/res/android">
    <item android:id="@+id/user_color">
        <shape android:shape="rectangle">
            <solid android:color="#000000" />
        </shape>
    </item>
    <item android:right="25dp">
        <shape android:shape="rectangle">
            <solid android:color="@color/user_background" />
        </shape>
    </item>
</layer-list>

我怎么称呼形状:

<LinearLayout
    android:orientation="horizontal"
    android:layout_width="fill_parent"
    android:layout_height="fill_parent"
    android:background="@drawable/shape">

如何以编程方式更改带有id的矩形形状的颜色user_color？

Answer 1

int colorToPaint = getResources().getColor(android.R.color.white);// any color you want
Drawable tempDrawable = getResources().getDrawable(R.drawable.xml_layout);
LayerDrawable bubble = (LayerDrawable) tempDrawable; //cast to root element in xml
GradientDrawable solidColor = (GradientDrawable) bubble.findDrawableByLayerId(R.id.user_color);
solidColor.setColor(colorToPaint);