Ben*_*min 11 java java-8 java-time
我正在尝试使用java 8 DateTime API解析日期时间字符串.
要解析的字符串包含日期,月份,年份和AM/PM标记,例如17/02/2015 PM.我使用以下模式:dd/MM/yyyy aa我希望解析的LocalDateTime时间部分设置为12:00:00或00:00:00取决于AM/PM标记.
使用以前的java.text.SimpleDateFormatAPI,解析使用此模式按预期工作.
但是当我使用java 8 DateTime API并运行以下代码时:
LocalDateTime.parse("17/02/2015 PM", DateTimeFormatter.ofPattern("dd/MM/yyyy aa"));
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我得到以下异常:
Exception in thread "main" java.lang.IllegalArgumentException: Too many pattern letters: a
at java.time.format.DateTimeFormatterBuilder.parseField(DateTimeFormatterBuilder.java:1765)
at java.time.format.DateTimeFormatterBuilder.parsePattern(DateTimeFormatterBuilder.java:1604)
at java.time.format.DateTimeFormatterBuilder.appendPattern(DateTimeFormatterBuilder.java:1572)
at java.time.format.DateTimeFormatter.ofPattern(DateTimeFormatter.java:534)
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如果我将模式切换到dd/MM/yyyy a那时我得到了以下异常:
Exception in thread "main" java.time.format.DateTimeParseException: Text '17/02/2015 PM' could not be parsed: Unable to obtain LocalDateTime from TemporalAccessor: {AmPmOfDay=1},ISO resolved to 2015-02-17 of type java.time.format.Parsed
at java.time.format.DateTimeFormatter.createError(DateTimeFormatter.java:1918)
at java.time.format.DateTimeFormatter.parse(DateTimeFormatter.java:1853)
at java.time.LocalDateTime.parse(LocalDateTime.java:492)
Caused by: java.time.DateTimeException: Unable to obtain LocalDateTime from TemporalAccessor: {AmPmOfDay=1},ISO resolved to 2015-02-17 of type java.time.format.Parsed
at java.time.LocalDateTime.from(LocalDateTime.java:461)
at java.time.LocalDateTime$$Lambda$7/474675244.queryFrom(Unknown Source)
at java.time.format.Parsed.query(Parsed.java:226)
at java.time.format.DateTimeFormatter.parse(DateTimeFormatter.java:1849)
... 2 more
Caused by: java.time.DateTimeException: Unable to obtain LocalTime from TemporalAccessor: {AmPmOfDay=1},ISO resolved to 2015-02-17 of type java.time.format.Parsed
at java.time.LocalTime.from(LocalTime.java:409)
at java.time.LocalDateTime.from(LocalDateTime.java:457)
... 5 more
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当我进行反向操作,格式化时,它也很奇怪:
System.out.println(LocalDateTime.of(2015, 02, 17, 0, 0, 0).format(DateTimeFormatter.ofPattern("dd/MM/yyyy a")));
System.out.println(LocalDateTime.of(2015, 02, 17, 12, 0, 0).format(DateTimeFormatter.ofPattern("dd/MM/yyyy a")));
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分别打印17/02/2015 AM和17/02/2015 PM.
javadoc java.time.DateTimeFormatter表示(§Resolving,step#6):
- 如果至少有一个小时的可用时间,则形成LocalTime.这涉及提供分钟,秒和小数秒的默认值.
我的理解是,每天的字段时间是解析LocalDateTime所必需的......是否有办法仅使用AM/PM字段解析时间部分?
Tag*_*eev 12
您可以通过以下方式设置不可用字段的默认值DateTimeFormatterBuilder.parseDefaulting:
DateTimeFormatter formatter = new DateTimeFormatterBuilder()
.appendPattern("dd/MM/yyyy a")
.parseDefaulting(ChronoField.HOUR_OF_AMPM, 0) // this is required
.parseDefaulting(ChronoField.MINUTE_OF_HOUR, 0) // optional, but you can set other value
.parseDefaulting(ChronoField.SECOND_OF_MINUTE, 0) // optional as well
.toFormatter();
System.out.println(LocalDateTime.parse("17/02/2015 PM", formatter)); // 2015-02-17T12:00
System.out.println(LocalDateTime.parse("17/02/2015 AM", formatter)); // 2015-02-17T00:00
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