如何按升序顺序对ArrayList <Object>进行排序

Question

我需要ArrayList<Object>根据名称按升序排序(自定义对象).为此我正在使用比较法

我的ArrayList:

ArrayList<Model> modelList = new ArrayList<Model>();

我正在使用的代码:

   Comparator<Model> comparator = new Comparator<Model>() {
            @Override
            public int compare(CarsModel lhs, CarsModel rhs) {

                String  left = lhs.getName();
                String right = rhs.getName();

                return left.compareTo(right);

            }
        };

   ArrayList<Model> sortedModel = Collections.sort(modelList,comparator);

//While I try to fetch the sorted ArrayList, I am getting error message 

我完全陷入困境,真的不知道如何继续进行以获得排序列表ArrayList<Object>.请帮我解决一下这个.任何帮助和解决方案对我都有帮助.我发布了我的确切场景供您参考.提前致谢.

例:

ArrayList<Model> modelList = new ArrayList<Model>();
modelList.add(new Model("chandru"));
modelList.add(new Model("mani"));
modelList.add(new Model("vivek"));
modelList.add(new Model("david"));

正常清单:

for(Model mod : modelList){
  Log.i("names", mod.getName());
}

输出:

chandru
mani
vivek
david

排序后我的要求如下:

for(Model mod : modelList){
  Log.i("names", mod.getName());
}

输出:

chandru
david
mani
vivek

Answer 1

你的方法是对的.让你的Comparator内心像在下面的例子中(或者可以改为创建一个新的类):

ArrayList<Model> modelList = new ArrayList<>();
modelList.add(new Model("chandru"));
modelList.add(new Model("mani"));
modelList.add(new Model("vivek"));
modelList.add(new Model("david"));

Collections.sort(modelList, new Comparator<Model>() {
    @Override
    public int compare(Model lhs, Model rhs) {
        return lhs.getName().compareTo(rhs.getName());
    }
});

输出:

chandru
david
mani
vivek

Answer 2

 Collections.sort(actorsList, new Comparator<Actors>() {
      @Override
      public int compare(Actors lhs, Actors rhs) {
       return lhs.getName().compareTo(rhs.getName());
     }
    });