计算下次执行cron作业的时间

Question

我有一个cron"时间定义"

1 * * * * (every hour at xx:01)
2 5 * * * (every day at 05:02)
0 4 3 * * (every third day of the month at 04:00)
* 2 * * 5 (every minute between 02:00 and 02:59 on fridays)

我有一个unix时间戳.

有没有一种明显的方法可以找到(计算)下一次(在给定的时间戳之后)该作业将被执行？

我正在使用PHP,但问题应该与语言无关.

[更新]

" PHP Cron Parser "类(由Ray建议)计算CRON作业应该执行的最后时间,而不是下次.

为了更容易:在我的情况下,cron时间参数只是绝对的,单个数字或"*".没有时间范围,也没有"*/5"间隔.

Answer 1

这是一个基于dlamblin的伪代码的PHP项目.

它可以计算CRON表达式的下一个运行日期,CRON表达式的上一个运行日期,并确定CRON表达式是否与给定时间匹配.您可以跳过此CRON表达式解析器完全实现CRON:

1. 范围增量(例如*/12,3-59/15)
2. 间隔时间(例如1-4,MON-FRI,JAN-MAR)
3. 列表(例如1,2,3 | JAN,MAR,DEC)
4. 一个月的最后一天(例如L)
5. 最后给出一个月的工作日(例如5L)
6. Nth给出一个月的工作日(例如3#2,1-1,MON#4)
7. 工作日最接近一个月的某一天(例如15W,1W,30W)

https://github.com/mtdowling/cron-expression

用法(PHP 5.3+):

<?php

// Works with predefined scheduling definitions
$cron = Cron\CronExpression::factory('@daily');
$cron->isDue();
$cron->getNextRunDate();
$cron->getPreviousRunDate();

// Works with complex expressions
$cron = Cron\CronExpression::factory('15 2,6-12 */15 1 2-5');
$cron->getNextRunDate();

Answer 2

这基本上与检查当前时间是否符合条件相反.像这样的东西:

//Totaly made up language
next = getTimeNow();
next.addMinutes(1) //so that next is never now
done = false;
while (!done) {
  if (cron.minute != '*' && next.minute != cron.minute) {
    if (next.minute > cron.minute) {
      next.addHours(1);
    }
    next.minute = cron.minute;
  }
  if (cron.hour != '*' && next.hour != cron.hour) {
    if (next.hour > cron.hour) {
      next.hour = cron.hour;
      next.addDays(1);
      next.minute = 0;
      continue;
    }
    next.hour = cron.hour;
    next.minute = 0;
    continue;
  }
  if (cron.weekday != '*' && next.weekday != cron.weekday) {
    deltaDays = cron.weekday - next.weekday //assume weekday is 0=sun, 1 ... 6=sat
    if (deltaDays < 0) { deltaDays+=7; }
    next.addDays(deltaDays);
    next.hour = 0;
    next.minute = 0;
    continue;
  }
  if (cron.day != '*' && next.day != cron.day) {
    if (next.day > cron.day || !next.month.hasDay(cron.day)) {
      next.addMonths(1);
      next.day = 1; //assume days 1..31
      next.hour = 0;
      next.minute = 0;
      continue;
    }
    next.day = cron.day
    next.hour = 0;
    next.minute = 0;
    continue;
  }
  if (cron.month != '*' && next.month != cron.month) {
    if (next.month > cron.month) {
      next.addMonths(12-next.month+cron.month)
      next.day = 1; //assume days 1..31
      next.hour = 0;
      next.minute = 0;
      continue;
    }
    next.month = cron.month;
    next.day = 1;
    next.hour = 0;
    next.minute = 0;
    continue;
  }
  done = true;
}

我可能写了一点倒退.如果在每个主要部分中,如果不是大于检查而只是将当前时间等级增加1并将较小的时间等级设置为0然后继续,则它可以更短.然而,你会循环更多.像这样:

//Shorter more loopy version
next = getTimeNow().addMinutes(1);
while (true) {
  if (cron.month != '*' && next.month != cron.month) {
    next.addMonths(1);
    next.day = 1;
    next.hour = 0;
    next.minute = 0;
    continue;
  }
  if (cron.day != '*' && next.day != cron.day) {
    next.addDays(1);
    next.hour = 0;
    next.minute = 0;
    continue;
  }
  if (cron.weekday != '*' && next.weekday != cron.weekday) {
    next.addDays(1);
    next.hour = 0;
    next.minute = 0;
    continue;
  }
  if (cron.hour != '*' && next.hour != cron.hour) {
    next.addHours(1);
    next.minute = 0;
    continue;
  }
  if (cron.minute != '*' && next.minute != cron.minute) {
    next.addMinutes(1);
    continue;
  }
  break;
}

Answer 3

对于任何感兴趣的人,这是我的最终PHP实现,它几乎等于dlamblin伪代码:

class myMiniDate {
    var $myTimestamp;
    static private $dateComponent = array(
                                    'second' => 's',
                                    'minute' => 'i',
                                    'hour' => 'G',
                                    'day' => 'j',
                                    'month' => 'n',
                                    'year' => 'Y',
                                    'dow' => 'w',
                                    'timestamp' => 'U'
                                  );
    static private $weekday = array(
                                1 => 'monday',
                                2 => 'tuesday',
                                3 => 'wednesday',
                                4 => 'thursday',
                                5 => 'friday',
                                6 => 'saturday',
                                0 => 'sunday'
                              );

    function __construct($ts = NULL) { $this->myTimestamp = is_null($ts)?time():$ts; }

    function __set($var, $value) {
        list($c['second'], $c['minute'], $c['hour'], $c['day'], $c['month'], $c['year'], $c['dow']) = explode(' ', date('s i G j n Y w', $this->myTimestamp));
        switch ($var) {
            case 'dow':
                $this->myTimestamp = strtotime(self::$weekday[$value], $this->myTimestamp);
                break;

            case 'timestamp':
                $this->myTimestamp = $value;
                break;

            default:
                $c[$var] = $value;
                $this->myTimestamp = mktime($c['hour'], $c['minute'], $c['second'], $c['month'], $c['day'], $c['year']);
        }
    }


    function __get($var) {
        return date(self::$dateComponent[$var], $this->myTimestamp);
    }

    function modify($how) { return $this->myTimestamp = strtotime($how, $this->myTimestamp); }
}


$cron = new myMiniDate(time() + 60);
$cron->second = 0;
$done = 0;

echo date('Y-m-d H:i:s') . '<hr>' . date('Y-m-d H:i:s', $cron->timestamp) . '<hr>';

$Job = array(
            'Minute' => 5,
            'Hour' => 3,
            'Day' => 13,
            'Month' => null,
            'DOW' => 5,
       );

while ($done < 100) {
    if (!is_null($Job['Minute']) && ($cron->minute != $Job['Minute'])) {
        if ($cron->minute > $Job['Minute']) {
            $cron->modify('+1 hour');
        }
        $cron->minute = $Job['Minute'];
    }
    if (!is_null($Job['Hour']) && ($cron->hour != $Job['Hour'])) {
        if ($cron->hour > $Job['Hour']) {
            $cron->modify('+1 day');
        }
        $cron->hour = $Job['Hour'];
        $cron->minute = 0;
    }
    if (!is_null($Job['DOW']) && ($cron->dow != $Job['DOW'])) {
        $cron->dow = $Job['DOW'];
        $cron->hour = 0;
        $cron->minute = 0;
    }
    if (!is_null($Job['Day']) && ($cron->day != $Job['Day'])) {
        if ($cron->day > $Job['Day']) {
            $cron->modify('+1 month');
        }
        $cron->day = $Job['Day'];
        $cron->hour = 0;
        $cron->minute = 0;
    }
    if (!is_null($Job['Month']) && ($cron->month != $Job['Month'])) {
        if ($cron->month > $Job['Month']) {
            $cron->modify('+1 year');
        }
        $cron->month = $Job['Month'];
        $cron->day = 1;
        $cron->hour = 0;
        $cron->minute = 0;
    }

    $done = (is_null($Job['Minute']) || $Job['Minute'] == $cron->minute) &&
            (is_null($Job['Hour']) || $Job['Hour'] == $cron->hour) &&
            (is_null($Job['Day']) || $Job['Day'] == $cron->day) &&
            (is_null($Job['Month']) || $Job['Month'] == $cron->month) &&
            (is_null($Job['DOW']) || $Job['DOW'] == $cron->dow)?100:($done+1);
}

echo date('Y-m-d H:i:s', $cron->timestamp) . '<hr>';

Answer 4

使用此功能:

function parse_crontab($time, $crontab)
         {$time=explode(' ', date('i G j n w', strtotime($time)));
          $crontab=explode(' ', $crontab);
          foreach ($crontab as $k=>&$v)
                  {$v=explode(',', $v);
                   foreach ($v as &$v1)
                           {$v1=preg_replace(array('/^\*$/', '/^\d+$/', '/^(\d+)\-(\d+)$/', '/^\*\/(\d+)$/'),
                                             array('true', '"'.$time[$k].'"==="\0"', '(\1<='.$time[$k].' and '.$time[$k].'<=\2)', $time[$k].'%\1===0'),
                                             $v1
                                            );
                           }
                   $v='('.implode(' or ', $v).')';
                  }
          $crontab=implode(' and ', $crontab);
          return eval('return '.$crontab.';');
         }
var_export(parse_crontab('2011-05-04 02:08:03', '*/2,3-5,9 2 3-5 */2 *'));
var_export(parse_crontab('2011-05-04 02:08:03', '*/8 */2 */4 */5 *'));

编辑也许这更具可读性:

<?php

    function parse_crontab($frequency='* * * * *', $time=false) {
        $time = is_string($time) ? strtotime($time) : time();
        $time = explode(' ', date('i G j n w', $time));
        $crontab = explode(' ', $frequency);
        foreach ($crontab as $k => &$v) {
            $v = explode(',', $v);
            $regexps = array(
                '/^\*$/', # every 
                '/^\d+$/', # digit 
                '/^(\d+)\-(\d+)$/', # range
                '/^\*\/(\d+)$/' # every digit
            );
            $content = array(
                "true", # every
                "{$time[$k]} === 0", # digit
                "($1 <= {$time[$k]} && {$time[$k]} <= $2)", # range
                "{$time[$k]} % $1 === 0" # every digit
            );
            foreach ($v as &$v1)
                $v1 = preg_replace($regexps, $content, $v1);
            $v = '('.implode(' || ', $v).')';
        }
        $crontab = implode(' && ', $crontab);
        return eval("return {$crontab};");
    }

用法:

<?php
if (parse_crontab('*/5 2 * * *')) {
    // should run cron
} else {
    // should not run cron
}

Answer 5

基于@dlamblin 的想法创建了用于计算下一次运行时间的 javascript API。支持秒和年。尚未对其进行全面测试，因此预计会出现错误，但如果发现任何错误，请告诉我。

存储库链接： https: //bitbucket.org/nevity/cronner