Rei*_*ard 5 c# entity-framework ef-code-first
我正在尝试将两个字段组合成一个带有EF6的唯一索引.但update-database命令不会将"Owner"字段添加到索引中.我在想它是因为它不是原始类型而是FK,但我不确定如何解决它.
public class Fund
{
[Key]
public int FundId { get; set; }
[Required]
[Index("IX_FundNameAndOwner", IsUnique = true, Order = 1)]
[Index("IX_FundIdentifierAndOwner", IsUnique = true, Order=1)]
public ApplicationUser Owner { get; set; }
[Required]
[Index("IX_FundNameAndOwner", IsUnique = true, Order=2)]
[MaxLength(25)]
public string Name { get; set; }
[Required]
[Index("IX_FundIdentifierAndOwner", IsUnique = true, Order=2)]
[MaxLength(25)]
public string Identifier { get; set; }
public double Balance { get; set; }
}
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生成的索引:
创建独特的非集群索引[IX_FundIdentifierAndOwner] ON [dbo].[Funds]([Identifier] ASC);
创建独特的非集群索引[IX_FundNameAndOwner] ON [dbo].[Funds]([Name] ASC);
创建非集群索引[IX_Owner_Id] ON [dbo].[Funds]([Owner_Id] ASC);
任何帮助是极大的赞赏!
小智 2
当您创建导航属性(引用另一个表)时,您应该指定用作外键的列名。如果您不这样做,EF 会假定它是一个名为 Objectname_Id 的列。
您可以在 sql 代码中看到它调用您的列 [Owner_Id]。问题是,当您这样做时,您无法控制该列的数据注释。
尝试这个
public class Fund
{
[Key]
public int FundId { get; set; }
[Required]
[Index("IX_FundNameAndOwner", IsUnique = true, Order = 1)]
[Index("IX_FundIdentifierAndOwner", IsUnique = true, Order = 1)]
public int OwnerId { get; set; } // <---- ADD THIS!
public virtual ApplicationUser Owner { get; set; }
[Required]
[Index("IX_FundNameAndOwner", IsUnique = true, Order = 2)]
[MaxLength(25)]
public string Name { get; set; }
[Required]
[Index("IX_FundIdentifierAndOwner", IsUnique = true, Order = 2)]
[MaxLength(25)]
public string Identifier { get; set; }
public double Balance { get; set; }
}
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添加名为 ObjectId(或 Objec_Id)的列 EF 按照约定理解该列是针对属性 Owner 的。
这是迁移生成的脚本:
CREATE TABLE [dbo].[Funds] (
[FundId] [int] NOT NULL IDENTITY,
[OwnerId] [int] NOT NULL,
[Name] [nvarchar](25) NOT NULL,
[Identifier] [nvarchar](25) NOT NULL,
[Balance] [float] NOT NULL,
CONSTRAINT [PK_dbo.Funds] PRIMARY KEY ([FundId])
)
CREATE UNIQUE INDEX [IX_FundIdentifierAndOwner] ON [dbo].[Funds]([OwnerId], [Identifier])
CREATE UNIQUE INDEX [IX_FundNameAndOwner] ON [dbo].[Funds]([OwnerId], [Name])
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以下是默认的Code First Conventions的解释。
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