如何将两个数组合并到字典中？

Question

我有2个数组:

    var identic = [String]()
    var linef = [String]()

我已经附上了数据.现在出于可用性目的,我的目标是将它们全部组合成具有以下结构的字典

FullStack = ["identic 1st value":"linef first value", "identic 2nd value":"linef 2nd value"]

我一直在网上浏览,无法找到一个可行的解决方案.

任何想法都非常感谢.

谢谢!

Answer 1

从Xcode 9.0开始,您可以简单地执行以下操作:

var identic = [String]()
var linef = [String]()

// Add data...

let fullStack = Dictionary(uniqueKeysWithValues: zip(identic, linef))

如果您的密钥不能保证是唯一的,请改用:

let fullStack =
    Dictionary(zip(identic, linef), uniquingKeysWith: { (first, _) in first })

要么

let fullStack =
    Dictionary(zip(identic, linef), uniquingKeysWith: { (_, last) in last })

文档:

• https://developer.apple.com/documentation/swift/dictionary/2894798-init

• https://developer.apple.com/documentation/swift/dictionary/2892961-init

Answer 2

这听起来像是一份工作enumerated()!

var arrayOne: [String] = []
var arrayTwo: [String] = []

var dictionary: [String: String] = [:]

for (index, element) in arrayOne.enumerated() {
    dictionary[element] = arrayTwo[index]
}

但是,如果您想要专业方法,请使用扩展名:

extension Dictionary {
    public init(keys: [Key], values: [Value]) {
        precondition(keys.count == values.count)

        self.init()

        for (index, key) in keys.enumerate() {
            self[key] = values[index]
        }
    }
}

编辑: enumerate() → enumerated()(Swift 3→Swift 4)

Answer 3

一种稍微不同的方法,它不需要数组具有相同的长度,因为该zip函数将安全地处理它.

extension Dictionary {
    init(keys: [Key], values: [Value]) {
        self.init()

        for (key, value) in zip(keys, values) {
            self[key] = value
        }
    }
}

Answer 4

如果您想更安全并确保每次都选择较小的数组(如果第二个数组小于第一个数组,那么您不会崩溃),那么执行以下操作:

var identic = ["A", "B", "C", "D"]
var linef = ["1", "2", "3"]

var Fullstack = [String: String]()
for i in 0..<min(linef.count, identic.count) {
    Fullstack[identic[i]] = linef[i]
}

print(Fullstack) // "[A: 1, B: 2, C: 3]"