int*_*lex 10 python python-imaging-library
我在Python中有一个二进制数组:
data = [0, 1, 1, 0, 1, 0, 1, 1, 0, 1, 0, 0, 0, 0, 0, 1...]
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我想取出这些数据并将其保存为位图,其中"0"对应于白色,"1"对应于黑色.我知道数组中有2500个数字,对应于50x50位图.我已经下载并安装了PIL,但我不确定如何将它用于此目的.如何将此数组转换为相应的图像?
ozg*_*gur 16
您可以使用Image.newwith 1模式并将每个整数作为像素放在初始图像中:
>>> from PIL import Image
>>> import random
>>> data = [random.choice((0, 1)) for _ in range(2500)]
>>> data[:] = [data[i:i + 50] for i in range(0, 2500, 50)]
>>> print data
[[0, 1, 0, 0, 1, ...], [0, 1, 1, 0, 1, ...], [1, 1, 0, 1, ...], ...]
>>> img = Image.new('1', (50, 50))
>>> pixels = img.load()
>>> for i in range(img.size[0]):
... for j in range(img.size[1]):
... pixels[i, j] = data[i][j]
>>> img.show()
>>> img.save('/tmp/image.bmp')
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在numpy和matplotlib这样做将是这样:
import matplotlib.pyplot as plt
import matplotlib.cm as cm
import numpy as np
plt.imsave('filename.png', np.array(data).reshape(50,50), cmap=cm.gray)
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看到这个