将复合Java对象转换为CSV

aaz*_*eem 2 java csv json jackson org.json

我有一个对象,例如Response.java,看起来像以下内容:

class Response
{
   private User user;  // has firstName, lastName, age etc.
   private Address address; // has city, state, country etc.
   private OrderInfo orderInfo;  // has orderNumber, orderDate etc.

   // constuctors, getters/setters follow

}
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我需要将这些对象的列表转换为csv,所以我的最终目标是:

firstName, lastName, age, city, state, country, latitude, orderNumber, orderDate
john, doe, 25, dallas, tx, usa, somelat, 101, 08/17/2015
jane, doe, 21, atlant, ga, usa, somelat, 102, 08/15/2015
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我尝试使用两个库-杰克逊(csv数据格式),org.json(JsonArray),但是我无法获得所需的结果。

这是我的杰克逊csv代码:

Response response = getResponse();
final CsvMapper mapper = new CsvMapper();
final CsvSchema schema = mapper.schemaFor(Response.class);
final String csv = mapper.writer(schema).writeValueAsString(response);
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随着杰克逊,我越来越

com.fasterxml.jackson.core.JsonGenerationException: CSV generator does not support Object values for properties
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有没有一种方法可以按照我需要的方式将复合对象转换为csv(只是没有json的字段(如分组))?

Col*_*nMc 7

因此,我运行了您在测试项目中使用的类似代码,看起来您将需要在所有对象(用户,地址和OrderInfo)上使用@JsonUnwrapped。

Jackson CSV不支持将对象作为属性,这就是为什么会出现该异常的原因。这是Github上的问题:Jackson CSV对象属性问题

这是我用来验证这一点的示例代码:

Test response = new Test();
response.setNum(1);
Stub s = new Stub();
s.setAge("12");
s.setName("Colin");
response.setS(s);
final CsvMapper mapper = new CsvMapper();
final CsvSchema schema = mapper.schemaFor(Test.class);
final String csv = mapper.writer(schema.withUseHeader(true)).writeValueAsString(response);
System.out.println(csv);
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上面的代码输出如下:

num,age,name
1,12,Colin
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