如何使用JPA和Spring在列表中找到包含字段的不同行？

Question

我使用Spring连接到数据库.我有一个扩展接口CrudRepository<People, Long>这是我想在db上执行的查询:SELECT DISTINCT name FROM people WHERE name NOT IN UserInputSet.我更愿意在没有任何sql注释的情况下完成它,所以如果没有那么好就可以NOT.

有办法吗？我查看了春季文档,但我找不到任何内容(http://docs.spring.io/spring-data/jpa/docs/current/reference/html/#repositories.query-methods.query-creation)

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这就是我累了,但它不起作用.

@Query("SELECT DISTINCT name FROM people WHERE name NOT IN (?1)")
List<String> findNonReferencedNames(List<String> names);

这是我得到的例外:

Error creating bean with name 'peopleRepository': Invocation of init method failed; nested exception is java.lang.IllegalArgumentException: Validation failed for query for method public abstract java.util.List de.test.tasks.persistence.PeopleRepository.findNonReferencedNames(java.util.List)!

和

Caused by: java.lang.IllegalArgumentException: org.hibernate.hql.internal.ast.QuerySyntaxException: people is not mapped [SELECT name FROM people WHERE name NOT IN (?1)]

Answer 1

我终于能够找到一个没有@Query注释的简单解决方案.

List<People> findDistinctByNameNotIn(List<String> names);

当然,我得到的是人物而不是弦乐.然后我可以在java中进行更改.

Answer 2

您是否尝试过重写这样的查询？

@Query("SELECT DISTINCT p.name FROM People p WHERE p.name NOT IN ?1")
List<String> findNonReferencedNames(List<String> names);

注意,我假设你的实体类是命名的People,而不是people.

Answer 3

@Query("SELECT DISTINCT name FROM people WHERE name NOT IN (:names)")
List<String> findNonReferencedNames(@Param("names") List<String> names);

Answer 4

@Query("SELECT distinct new com.model.referential.Asset(firefCode,firefDescription) FROM AssetClass ")
List<AssetClass> findDistinctAsset();