如何将Javascript数组值传递给PHP,然后使用此值发送MySQL查询?

Oen*_*n44 0 javascript php arrays


正如我在标题中提到的,如何将JS数组值传递给PHP然后使用mysqli发送?

以下是有助于以后发送值的函数.

function getPlayerName() {
    return player.Name;
}

function getPlayerClass() {
    return player.Class;
}

function getPlayerLevel() {
    return player.Level;
}
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对我来说最重要的是我如何将这个数组传递给PHP?

@Edit
我正在使用store.js来保存播放器数组值(Local Storrage).这是在创建新玩家时保存它的功能.

function saveData(){
    var playerName = document.getElementById('nickname');
    var warriorClass = document.getElementById('warrior');
    var mageClass = document.getElementById('mage');
    var archerClass = document.getElementById('archer');

    if(warriorClass.checked){
        store.set('player', {
            Name: playerName.value,
            Class: 'Warrior',
            Level: playerLevel,
            XP: playerXP,
            HP: playerHP,
            MaxHP: playerMaxHP
        });
    }
    else if(mageClass.checked){
        store.set('player', {
            Name: playerName.value,
            Class: 'Mage',
            Level: playerLevel,
            XP: playerXP,
            HP: playerHP,
            MaxHP: playerMaxHP
        });
    }
    else if(archerClass.checked){
        store.set('player', {
            Name: playerName.value,
            Class: 'Archer',
            Level: playerLevel,
            XP: playerXP,
            HP: playerHP,
            MaxHP: playerMaxHP
        });
    }
}
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@ Edit2
有了Skamielina的建议我做了这样的事情:

$.ajax({
      method: "POST",
      url: "top15.php",
      data: { Name: player.Name, Class: player.Class, Level: player.Level }
    })
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并且top15.php有这个:

<?php
        echo 'Name: ' . $_POST['Name'] . '<br/>';
        echo 'Level: ' . $_POST['Level'] . '<br/>';
        echo 'Class: ' . $_POST['Class'] . '<br/>';
?>
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现在,在网页上

Name: 
Level: 
Class: 
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但是,FireBug控制台显示

Name: Oen<br/>Level: 1<br/>Class: Mage<br/> 
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愚蠢的我......不是阵列,我的意思是变量.天啊,抱歉这个错误:x

Ska*_*ina 6

使用jQuery和$.ajax函数(参见docs):

$.ajax({
  method: "POST",
  url: "some.php",
  data: { name: player.Name, class: player.Class, level: player.Level }
})
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接下来,你需要有php文件来处理来自浏览器的请求,并最终返回结果.