使用内部类输入类型调用AWS lambda函数

ger*_*esc 5 python amazon-web-services java-8 boto3 aws-lambda

我像这样定义了lambda 函数并将其上传到亚马逊:

@Override
public String handleRequest(Request input, Context context) {
    String template = "%s ${greeting}";
    StrSubstitutor ss = new StrSubstitutor(input.replaceables);
    String inputted = String.format(template, input.rawValues[0]);
    return ss.replace(inputted);
}
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请求类定义(内部类):

public class Request {
    String[] rawValues;
    HashMap<String, String> replaceables;

    public Request(){
        replaceables = new HashMap<String, String>();
    }

    //...getter and setters
}
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然后从boto3调用它并得到这个答案:

>>> client = boto3.client('lambda', 'us-west-2')
>>> resp = client.invoke(FunctionName='myfunction', InvocationType='RequestResponse', Payload="""{"rawValues": ["jero"], "replaceables": {"greeting": "world"}}""")
>>> resp['Payload'].read()
'{"errorMessage":"An error occurred during JSON parsing","errorType":"java.lang.RuntimeException","stackTrace":[],"cause":{"errorMessage":"com.fasterxml.jackson.databind.JsonMappingException: No suitable constructor found for type [simple type, class mypackage.functions.Demo$Request]: can not instantiate from JSON object (missing default constructor or creator, or perhaps need to add/enable type information?)\\n at [Source: lambdainternal.util.NativeMemoryAsInputStream@735b478; line: 1, column: 2]","errorType":"java.io.UncheckedIOException","stackTrace":[],"cause":{"errorMessage":"No suitable constructor found for type [simple type, class mypackage.functions.Demo$Request]: can not instantiate from JSON object (missing default constructor or creator, or perhaps need to add/enable type information?)\\n at [Source: lambdainternal.util.NativeMemoryAsInputStream@735b478; line: 1, column: 2]","errorType":"com.fasterxml.jackson.databind.JsonMappingException","stackTrace":["com.fasterxml.jackson.databind.JsonMappingException.from(JsonMappingException.java:148)","com.fasterxml.jackson.databind.deser.BeanDeserializerBase.deserializeFromObjectUsingNonDefault(BeanDeserializerBase.java:1080)","com.fasterxml.jackson.databind.deser.BeanDeserializer.deserializeFromObject(BeanDeserializer.java:295)","com.fasterxml.jackson.databind.deser.BeanDeserializer.deserialize(BeanDeserializer.java:142)","com.fasterxml.jackson.databind.ObjectReader._bindAndClose(ObjectReader.java:1441)","com.fasterxml.jackson.databind.ObjectReader.readValue(ObjectReader.java:1047)"]}}}'
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在亚马逊控制台测试时显示完整错误:

"cause": {
  "errorMessage": "No suitable constructor found for type [simple type, class mypackage.functions.Demo$Request]: can not instantiate from JSON object (missing default constructor or creator, or perhaps need to add/enable type information?)\n at [Source: lambdainternal.util.NativeMemoryAsInputStream@2c9f9fb0; line: 1, column: 4]",
  "errorType": "com.fasterxml.jackson.databind.JsonMappingException",
  "stackTrace": [
    "com.fasterxml.jackson.databind.JsonMappingException.from(JsonMappingException.java:148)",
    "com.fasterxml.jackson.databind.deser.BeanDeserializerBase.deserializeFromObjectUsingNonDefault(BeanDeserializerBase.java:1080)",
    "com.fasterxml.jackson.databind.deser.BeanDeserializer.deserializeFromObject(BeanDeserializer.java:295)",
    "com.fasterxml.jackson.databind.deser.BeanDeserializer.deserialize(BeanDeserializer.java:142)",
    "com.fasterxml.jackson.databind.ObjectReader._bindAndClose(ObjectReader.java:1441)",
    "com.fasterxml.jackson.databind.ObjectReader.readValue(ObjectReader.java:1047)"
  ]
}
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因此,返回的主要错误让我认为我的Request类定义存在问题,该定义基本上定义了未序列化 JSON 的接收者"""{"rawValues": ["jero"], "replaceable": {"greeting": "world"}}"""。在文档中,指出支持 Map java 类型作为输入类型,但我无法使其工作。您知道将 JSON 字典映射到 Java 映射的 java 函数示例吗?

Com*_*uid 4

非静态内部类不能从外部类的实例外部构造。

尝试将内部类 ( Request) 设为静态,例如:

public static class Request {
    ...
}
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