Kvo*_*the 7 python fuzzy-search string-matching fuzzywuzzy
我正在尝试模糊匹配两个csv文件,每个文件包含一列相似但不相同的名称.
我的代码到目前为止如下:
import pandas as pd
from pandas import DataFrame
from fuzzywuzzy import process
import csv
save_file = open('fuzzy_match_results.csv', 'w')
writer = csv.writer(save_file, lineterminator = '\n')
def parse_csv(path):
with open(path,'r') as f:
reader = csv.reader(f, delimiter=',')
for row in reader:
yield row
if __name__ == "__main__":
## Create lookup dictionary by parsing the products csv
data = {}
for row in parse_csv('names_1.csv'):
data[row[0]] = row[0]
## For each row in the lookup compute the partial ratio
for row in parse_csv("names_2.csv"):
#print(process.extract(row,data, limit = 100))
for found, score, matchrow in process.extract(row, data, limit=100):
if score >= 60:
print('%d%% partial match: "%s" with "%s" ' % (score, row, found))
Digi_Results = [row, score, found]
writer.writerow(Digi_Results)
save_file.close()
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输出如下:
Name11 , 90 , Name25
Name11 , 85 , Name24
Name11 , 65 , Name29
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该脚本工作正常.输出符合预期.但我正在寻找的只是最好的匹配.
Name11 , 90 , Name25
Name12 , 95 , Name21
Name13 , 98 , Name22
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因此,我需要根据第2列中的最高值以某种方式删除第1列中的重复名称.它应该相当简单,但我似乎无法弄明白.任何帮助,将不胜感激.
fuzzywuzzy's process.extract()以反向排序顺序返回列表,最佳匹配首先出现.
因此,为了找到最佳匹配,您可以将limit参数设置为1,以便它只返回最佳匹配,如果大于60,则可以将其写入csv,就像您现在所做的那样.
示例 -
from fuzzywuzzy import process
## For each row in the lookup compute the partial ratio
for row in parse_csv("names_2.csv"):
for found, score, matchrow in process.extract(row, data, limit=1):
if score >= 60:
print('%d%% partial match: "%s" with "%s" ' % (score, row, found))
Digi_Results = [row, score, found]
writer.writerow(Digi_Results)
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使用process.extractOne()来自 FuzzyWuzzy可以大大简化您的几段代码。它不仅只返回最高匹配项,您还可以在函数调用中为其设置分数阈值,而不需要执行单独的逻辑步骤,例如:
process.extractOne(row, data, score_cutoff = 60)
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如果找到满足条件的匹配项,该函数将返回最高匹配项加上相应分数的元组。None否则它将返回。
我只是为自己写了同样的东西,但在熊猫中......
import pandas as pd
import numpy as np
from fuzzywuzzy import fuzz
from fuzzywuzzy import process
d1={1:'Tim','2':'Ted',3:'Sally',4:'Dick',5:'Ethel'}
d2={1:'Tam','2':'Tid',3:'Sally',4:'Dicky',5:'Aardvark'}
df1=pd.DataFrame.from_dict(d1,orient='index')
df2=pd.DataFrame.from_dict(d2,orient='index')
df1.columns=['Name']
df2.columns=['Name']
def match(Col1,Col2):
overall=[]
for n in Col1:
result=[(fuzz.partial_ratio(n, n2),n2)
for n2 in Col2 if fuzz.partial_ratio(n, n2)>50
]
if len(result):
result.sort()
print('result {}'.format(result))
print("Best M={}".format(result[-1][1]))
overall.append(result[-1][1])
else:
overall.append(" ")
return overall
print(match(df1.Name,df2.Name))
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我在这里使用了 50 的阈值 - 但它是可配置的。
Dataframe1 看起来像
Name
1 Tim
2 Ted
3 Sally
4 Dick
5 Ethel
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而 Dataframe2 看起来像
Name
1 Tam
2 Tid
3 Sally
4 Dicky
5 Aardvark
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所以运行它会产生匹配
['Tid', 'Tid', 'Sally', 'Dicky', ' ']
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希望这可以帮助。