如何使用JSON,jQuery向ASP.NET MVC Controller发布复杂对象数组？

Question

我当前的代码如下所示.如何将我的数组传递给控制器​​以及控制器操作必须接受哪种参数？

function getplaceholders() {
    var placeholders = $('.ui-sortable');
    var result = new Array();
    placeholders.each(function() {
        var ph = $(this).attr('id');
        var sections = $(this).find('.sort');
        var section;

        sections.each(function(i, item) {
            var sid = $(item).attr('id');

            result.push({ 'SectionId': sid, 'Placeholder': ph, 'Position': i });
        });
    });
    alert(result.toString());
    $.post(
        '/portal/Designer.mvc/SaveOrUpdate',
        result,
        function(data) {
            alert(data.Result);
        }, "json");
};

我的控制器动作方法看起来像

public JsonResult SaveOrUpdate(IList<PageDesignWidget> widgets)

Answer 1

我找到了解决方案.我使用Steve Gentile,jQuery和ASP.NET MVC的解决方案- 将JSON发送到Action - Revisited.

我的ASP.NET MVC视图代码如下所示:

function getplaceholders() {
        var placeholders = $('.ui-sortable');
        var results = new Array();
        placeholders.each(function() {
            var ph = $(this).attr('id');
            var sections = $(this).find('.sort');
            var section;

            sections.each(function(i, item) {
                var sid = $(item).attr('id');
                var o = { 'SectionId': sid, 'Placeholder': ph, 'Position': i };
                results.push(o);
            });
        });
        var postData = { widgets: results };
        var widgets = results;
        $.ajax({
            url: '/portal/Designer.mvc/SaveOrUpdate',
            type: 'POST',
            dataType: 'json',
            data: $.toJSON(widgets),
            contentType: 'application/json; charset=utf-8',
            success: function(result) {
                alert(result.Result);
            }
        });
    };

我的控制器动作用自定义属性修饰

[JsonFilter(Param = "widgets", JsonDataType = typeof(List<PageDesignWidget>))]
public JsonResult SaveOrUpdate(List<PageDesignWidget> widgets

可以在此处找到自定义属性的代码(链接现在已断开).

因为链接被破坏,所以这是JsonFilterAttribute的代码

public class JsonFilter : ActionFilterAttribute
{
    public string Param { get; set; }
    public Type JsonDataType { get; set; }
    public override void OnActionExecuting(ActionExecutingContext filterContext)
    {
        if (filterContext.HttpContext.Request.ContentType.Contains("application/json"))
        {
            string inputContent;
            using (var sr = new StreamReader(filterContext.HttpContext.Request.InputStream))
            {
                inputContent = sr.ReadToEnd();
            }
            var result = JsonConvert.DeserializeObject(inputContent, JsonDataType);
            filterContext.ActionParameters[Param] = result;
        }
    }
}

JsonConvert.DeserializeObject来自Json.NET

链接:使用Json.NET序列化和反序列化JSON

Answer 2

动作过滤器,jquery stringify,bleh ......

Peter,这个功能是MVC原生的.这是让MVC如此出色的事情之一.

$.post('SomeController/Batch', { 'ids': ['1', '2', '3']}, function (r) {
   ...
});

在行动中,

[HttpPost]
public ActionResult Batch(string[] ids)
{
}

奇迹般有效:

如果你正在使用jQuery 1.4+,那么你想看看设置传统模式:

jQuery.ajaxSettings.traditional = true;

如下所述:http://www.dovetailsoftware.com/blogs/kmiller/archive/2010/02/24/jquery-1-4-breaks-asp-net-mvc-actions-with-array-parameters

这甚至适用于复杂的物体.如果您有兴趣,可以查看有关模型绑定的MVC文档:http://msdn.microsoft.com/en-us/library/dd410405.aspx

Answer 3

在.NET4.5,MVC 5不需要小部件.

使用Javascript:

JS中的对象:

发布的机制.

    $('.button-green-large').click(function() {
        $.ajax({
            url: 'Quote',
            type: "POST",
            dataType: "json",
            data: JSON.stringify(document.selectedProduct),
            contentType: 'application/json; charset=utf-8',
        });
    });

C#

对象:

public class WillsQuoteViewModel
{
    public string Product { get; set; }

    public List<ClaimedFee> ClaimedFees { get; set; }
}

public partial class ClaimedFee //Generated by EF6
{
    public long Id { get; set; }
    public long JourneyId { get; set; }
    public string Title { get; set; }
    public decimal Net { get; set; }
    public decimal Vat { get; set; }
    public string Type { get; set; }

    public virtual Journey Journey { get; set; }
}

控制器:

[AcceptVerbs(HttpVerbs.Post)]
public ActionResult Quote(WillsQuoteViewModel data)
{
....
}

收到的对象:

希望这能为您节省一些时间.

Answer 4

使用同时使用JSON和纯XML的ASP.NET MVC创建REST API的下半部分,引用:

现在我们需要接受通过HTTP POST提供的JSON和XML有效负载.有时,您的客户可能希望一次上传一组对象以进行批处理.因此,他们可以使用JSON或XML格式上传对象.ASP.NET MVC中没有本机支持来自动解析发布的JSON或XML并自动映射到Action参数.所以,我写了一个过滤器来做到这一点."

然后,他实现了一个动作过滤器,它将JSON映射到C#对象,并显示代码.

Answer 5

首先下载这个JavaScript代码JSON2.js,它将帮助我们将对象序列化为字符串.

在我的例子中,我通过Ajax 发布了jqGrid的行:

    var commissions = new Array();
    // Do several row data and do some push. In this example is just one push.
    var rowData = $(GRID_AGENTS).getRowData(ids[i]);
    commissions.push(rowData);
    $.ajax({
        type: "POST",
        traditional: true,
        url: '<%= Url.Content("~/") %>' + AREA + CONTROLLER + 'SubmitCommissions',
        async: true,
        data: JSON.stringify(commissions),
        dataType: "json",
        contentType: 'application/json; charset=utf-8',
        success: function (data) {
            if (data.Result) {
                jQuery(GRID_AGENTS).trigger('reloadGrid');
            }
            else {
                jAlert("A problem ocurred during updating", "Commissions Report");
            }
        }
    });

现在在控制器上:

    [HttpPost]
    [JsonFilter(Param = "commissions", JsonDataType = typeof(List<CommissionsJs>))]
    public ActionResult SubmitCommissions(List<CommissionsJs> commissions)
    {
        var result = dosomething(commissions);
        var jsonData = new
        {
            Result = true,
            Message = "Success"
        };
        if (result < 1)
        {
            jsonData = new
            {
                Result = false,
                Message = "Problem"
            };
        }
        return Json(jsonData);
    }

创建一个JsonFilter类(感谢JSC参考).

    public class JsonFilter : ActionFilterAttribute
    {
        public string Param { get; set; }
        public Type JsonDataType { get; set; }
        public override void OnActionExecuting(ActionExecutingContext filterContext)
        {
            if (filterContext.HttpContext.Request.ContentType.Contains("application/json"))
            {
                string inputContent;
                using (var sr = new StreamReader(filterContext.HttpContext.Request.InputStream))
                {
                    inputContent = sr.ReadToEnd();
                }
                var result = JsonConvert.DeserializeObject(inputContent, JsonDataType);
                filterContext.ActionParameters[Param] = result;
            }
        }
    }

创建另一个类,以便过滤器可以将JSON字符串解析为实际的可操作对象:此类comissionsJS是我的jqGrid的所有行.

    public class CommissionsJs
    {
        public string Amount { get; set; }

        public string CheckNumber { get; set; }

        public string Contract { get; set; }
        public string DatePayed { get; set; }
        public string DealerName { get; set; }
        public string ID { get; set; }
        public string IdAgentPayment { get; set; }
        public string Notes { get; set; }
        public string PaymentMethodName { get; set; }
        public string RowNumber { get; set; }
        public string AgentId { get; set; }
    }

我希望这个例子有助于说明如何发布复杂的对象.