email.retr在电子邮件正文中包含中文字符时检索奇怪的= 20个字符

Question

    self.logger.info(msg)
    popinstance=poplib.POP3(self.account[0])
    self.logger.info(popinstance.getwelcome())
    popinstance.user(self.account[1])
    popinstance.pass_(self.account[2])
    try:
        (numMsgs, totalSize)=popinstance.stat()
        self.logger.info("POP contains " + str(numMsgs) + " emails")
        for thisNum in xrange(1, numMsgs + 1):
            try:
                (server_msg, body, octets)=popinstance.retr(thisNum)
            except:
                self.logger.error("Could not download email")
                raise
            text="\n".join(body)
            mesg=StringIO.StringIO(text)
            msg=rfc822.Message(mesg)
            MessageID=email.Utils.parseaddr(msg["Message-ID"])[1]
            self.logger.info("downloading email " + MessageID)
            emailpath=os.path.join(self._emailpath + self._inboxfolder + "\\" + self._sanitize_string(MessageID  + ".eml"))
            emailpath=self._replace_whitespace(emailpath)
            try:
                self._dual_dump(text,emailpath)
            except:
                pass
            self.logger.info(popinstance.dele(thisNum))
    finally:
        self.logger.info(popinstance.quit())

(server_msg,body,octets)= popinstance.retr(thisNum)在电子邮件包含中文字符时在电子邮件正文中返回= 20.

我该如何处理？

电子邮件的原始文本:

主题:(提单:4363-0192-809.015)SI FOR 15680XXXX436

= 20

亲

= 20

SI封闭

PLS向我们发送BL草案和债务说明

= 20

TKS

= 20

肉豆蔻酸

-----原始消息----- = 20

Answer 1

它可能是以quoted-printable编码的Space字符

Answer 2

使用quopri模块解码字符串.