访问有序默认字典中的对象

Question

我使用从订单的默认字典这里.问题是我不知道如何访问对象.

我期待这样的事情应该奏效

{% for zone in data %}
    {% for reservation in zone %}
        {{reservation}} # 1 | 2| 3
    {% endfor %}
{% endfor %}

---

数据有助于调试

{{data}}

OrderedDefaultDict(<type 'list'>, DefaultOrderedDict([('1', [<app.backoffice.models.Reservation object at 0x7f91c2c5ee10>, <app.backoffice.models.Reservation object at 0x7f91c2c732d0>, <app.backoffice.models.Reservation object at 0x7f91c2c73510>]), ('2', [<app.backoffice.models.Reservation object at 0x7f91c2c73790>, <app.backoffice.models.Reservation object at 0x7f91c32f9c50>]), ('3', [<app.backoffice.models.Reservation object at 0x7f91c2c733d0>, <app.backoffice.models.Reservation object at 0x7f91c2c73490>])]))

---

{% for zone in data %}
   {{zone}} # 1 | 2 | 3
   {{zone[0]}} # 1 | 2 | 3
{% endfor %}

Answer 1

当你遍历一个字典(甚至是一个子类)时,你得到了密钥 ; 如果要循环嵌套对象,则必须先将该键转换为值:

{% for zone in data %}
    {% for reservation in data[zone] %}
        {{reservation}}
    {% endfor %}
{% endfor %}

由于您不显示zone密钥,您也可以遍历字典值(使用dict.itervalues()以避免创建冗余列表对象):

{% for reservations in data.itervalues() %}
    {% for reservation in reservations %}
        {{reservation}}
    {% endfor %}
{% endfor %}

或者dict.iteritems()用来获取密钥和值:

{% for zone, reservations in data.iteritems() %}
    {{zone}}: 
    {% for reservation in reservations %}
        {{reservation}}
    {% endfor %}
{% endfor %}

在您自己的尝试中,zone只被设置为每个键,在您的情况下是单字符串('1','2'和'3').循环单个字符串或索引该字符串zone[0]只会导致显示一个字符.