Swift - 确定用开关按下哪个按钮

Question

我有4个按钮调用一个功能.根据按下哪个按钮,我需要隐藏按下后调用的功能内的按钮.我不知道按下了哪个按钮所以我试图为4个按钮中的每一个分配标签,以便通过标签识别它们并使用开关

我试过这个

            switch sender.tag {
            case 1:
                self.button1.hidden = true
            case 2:
                self.button2.hidden = true
            case 3:
                self.button3.hidden = true
            case 4:
                self.button4.hidden = true

            }

但这不起作用编译器说使用未解析的标识符'发送者'

怎么做到这一点？

编辑:

整体功能

  if self.allowMistakeVar {

        let mistakeAlert = UIAlertController(title: "Here is title!", message: "message of alert", preferredStyle: .Alert)
        let okay = UIAlertAction(title: "OK", style: .Cancel) { UIAlertAction in

            self.allowMistakeVar = false
            self.allowMistakeButton.enabled = false


            switch sender.tag {
            case answer1Text:
                self.answer1Text.hidden = true
            case answer2Text:
                self.answer2Text.hidden = true
            case answer3Text:
                self.answer3Text.hidden = true
            case answer4Text:
                self.answer4Text.hidden = true

            }

        }

        mistakeAlert.addAction(okay)
        self.presentViewController(mistakeAlert, animated: true, completion: nil )

    } else {

另一个案例..}

Answer 1

试试这个,

1)为每个按钮分配标签

Button1.tag=1
Button2.tag=2
Button3.tag=3
Button4.tag=4

2)然后检查您的常用按钮操作

func buttonClicked(sender: UIButton)
{
   switch sender.tag {
   case 1: self.sender.hidden = true //button1
           break;
   case 2: self.sender.hidden = true //button2
           break;
   case 3: self.sender.hidden = true //button3
           break;
   case 4: self.sender.hidden = true //button4
           break;
   default: ()
           break;
   }

}

Answer 2

为什么你总是想用标签来确定UIButton？如果被调用函数有一个sender参数,那么你知道通过这个参数调用函数的UIButton.

func buttonClicked(sender: UIButton)
{
   switch sender {
   case button1: // Do something
   case button2: // Do some other stuff
   ...
   default: ()
   }

}