Jersey,Tomcat:请求的资源不可用错误
Jak*_*ans 6 eclipse rest rad tomcat7 jersey-2.0
我一直在努力在RAD 8.5中使用Jersey和Tomcat设置RESTful服务.我查看了大量与我的错误相关的stackoverflow问题,但没有一个工作正常.我的控制台没有错误.
当我输入:http:// localhost:8080 /时,我得到Apache主页,所以服务器正在运行,但http:// localhost:8080/jersey/rest/hello或http:// localhost:8080/jersey /WEB-INF/classes/jersey/Hello.java 不起作用.
这是错误:(我的罐子库侧面)
这是我的 Hello.java
package jersey;
import javax.ws.rs.GET;
import javax.ws.rs.Path;
import javax.ws.rs.Produces;
import javax.ws.rs.core.MediaType;
@Path("/hello")
public class Hello {
// This method is called if TEXT_PLAIN is request
@GET
@Produces(MediaType.TEXT_PLAIN)
public String sayPlainTextHello() {
return "Hello Jersey";
}
// This method is called if XML is request
@GET
@Produces(MediaType.TEXT_XML)
public String sayXMLHello() {
return "<?xml version=\"1.0\"?>" + "<hello> Hello Jersey" + "</hello>";
}
@GET
@Produces(MediaType.TEXT_HTML)
public String sayHtmlHello() {
return "<html> " + "<title>" + "Hello Jersey" + "</title>"
+ "<body><h1>" + "Hello Jersey" + "</body></h1>" + "</html> ";
}
}
还有我的web.xml
<servlet>
<servlet-name>Jersey REST Service</servlet-name>
<servlet-class>org.glassfish.jersey.servlet.ServletContainer</servlet-class>
<init-param>
<param-name>jersey.config.server.provider.packages</param-name>
<param-value>com.example</param-value>
</init-param>
</servlet>
版本:
- Tomcat:7.0.663
- RAD:8.5
- 泽西岛:2.19
谢谢,
在回应Maciej
这工作!我需要添加<servlet-mapping>url模式/*.然后使用http:// localhost:8080/jersey/hello,我从服务器得到了回复!
<?xml version="1.0" encoding="UTF-8"?>
<web-app xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance"
xmlns="http://java.sun.com/xml/ns/javaee"
xsi:schemaLocation="http://java.sun.com/xml/ns/javaee http://java.sun.com/xml/ns/javaee/web-app_2_5.xsd"
id="jersey" version="2.5">
<servlet>
<servlet-name>jersey</servlet-name>
<servlet-class>org.glassfish.jersey.servlet.ServletContainer</servlet-class>
<init-param>
<param-name>jersey.config.server.provider.packages</param-name>
<param-value>jersey</param-value>
</init-param>
</servlet>
<servlet-mapping>
<servlet-name>jersey</servlet-name>
<url-pattern>/*</url-pattern>
</servlet-mapping>
</web-app>
您正在将已编译的代码部署到Tomcat,因此您将无法访问*.java资源.
注释@Path("/hello")指示资源可用的路径.
它被设置为:base URL + /your_path.将base URL基于您的应用程序名称,servlet和从URL模式web.xml:
<?xml version="1.0" encoding="UTF-8"?>
<web-app xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance"
xmlns="http://java.sun.com/xml/ns/javaee"
xsi:schemaLocation="http://java.sun.com/xml/ns/javaee http://java.sun.com/xml/ns/javaee/web-app_2_5.xsd"
id="jersey" version="2.5">
<servlet>
<servlet-name>jersey</servlet-name>
<servlet-class>org.glassfish.jersey.servlet.ServletContainer</servlet-class>
<init-param>
<param-name>jersey.config.server.provider.packages</param-name>
<param-value>jersey</param-value>
</init-param>
</servlet>
<servlet-mapping>
<servlet-name>jersey</servlet-name>
<url-pattern>/*</url-pattern>
</servlet-mapping>
</web-app>
同时将@Produces注释替换为@Consumes:
package jersey;
import javax.ws.rs.Consumes;
import javax.ws.rs.GET;
import javax.ws.rs.Path;
import javax.ws.rs.core.MediaType;
@Path("/hello")
public class Hello {
// This method is called if TEXT_PLAIN is request
@GET
@Consumes(MediaType.TEXT_PLAIN)
public String sayPlainTextHello() {
return "Hello Jersey";
}
// This method is called if XML is request
@GET
@Consumes(MediaType.TEXT_XML)
public String sayXMLHello() {
return "<?xml version=\"1.0\"?>" + "<hello> Hello Jersey" + "</hello>";
}
@GET
@Consumes(MediaType.TEXT_HTML)
public String sayHtmlHello() {
return "<html> " + "<title>" + "Hello Jersey" + "</title>"
+ "<body><h1>" + "Hello Jersey" + "</body></h1>" + "</html> ";
}
}
尝试:http:// localhost:8080/jersey/hello
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