Unpack multiple variables from sequence

Question

I am expecting the code below to print chr7.

import strutils

var splitLine = "chr7    127471196  127472363  Pos1  0  +".split()
var chrom, startPos, endPos = splitLine[0..2]
echo chrom

Instead it prints @[chr7, 127471196, 127472363].

Is there a way to unpack multiple values from sequences at the same time?

And what would the tersest way to do the above be if the elements weren't contiguous? For example:

var chrom, startPos, strand = splitLine[0..1, 5]

Gives the error:

read_bed.nim(8, 40) Error: type mismatch: got (seq[string], Slice[system.int], int literal(5))
but expected one of:
system.[](a: array[Idx, T], x: Slice[system.int])
system.[](s: string, x: Slice[system.int])
system.[](a: array[Idx, T], x: Slice[[].Idx])
system.[](s: seq[T], x: Slice[system.int])

  var chrom, startPos, strand = splitLine[0..1, 5]
                                         ^

Answer 1

这可以使用宏来完成。

import macros

macro `..=`*(lhs: untyped, rhs: tuple|seq|array): auto =
  # Check that the lhs is a tuple of identifiers.
  expectKind(lhs, nnkPar)
  for i in 0..len(lhs)-1:
    expectKind(lhs[i], nnkIdent)
  # Result is a statement list starting with an
  # assignment to a tmp variable of rhs.
  let t = genSym()
  result = newStmtList(quote do:
    let `t` = `rhs`)
  # assign each component to the corresponding
  # variable.
  for i in 0..len(lhs)-1:
    let v = lhs[i]
    # skip assignments to _.
    if $v.toStrLit != "_":
      result.add(quote do:
        `v` = `t`[`i`])

macro headAux(count: int, rhs: seq|array|tuple): auto =
  let t = genSym()
  result = quote do:
    let `t` = `rhs`
    ()
  for i in 0..count.intVal-1:
    result[1].add(quote do:
      `t`[`i`])

template head*(count: static[int], rhs: untyped): auto =
  # We need to redirect this through a template because
  # of a bug in the current Nim compiler when using
  # static[int] with macros.
  headAux(count, rhs)

var x, y: int
(x, y) ..= (1, 2)
echo x, y
(x, _) ..= (3, 4)
echo x, y
(x, y) ..= @[4, 5, 6]
echo x, y
let z = head(2, @[4, 5, 6])
echo z
(x, y) ..= head(2, @[7, 8, 9])
echo x, y

该..=宏元组解包或顺序分配。var (x, y) = (1, 2)例如，您可以使用 完成相同的操作，但也..=适用于 seq 和数组，并允许您重用变量。

所述head模板/宏提取所述第一count从一个元组，阵列或seqs并返回它们作为一个元组元素（其可以然后像任何其他元组被使用，例如用于与解构let或var）。