kru*_*pan 151 python validation networking ip-address
验证用户输入的IP有效的最佳方法是什么?它以字符串形式出现.
Dus*_*tin 176
不要解析它.请问.
import socket
try:
socket.inet_aton(addr)
# legal
except socket.error:
# Not legal
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tzo*_*zot 66
import socket
def is_valid_ipv4_address(address):
try:
socket.inet_pton(socket.AF_INET, address)
except AttributeError: # no inet_pton here, sorry
try:
socket.inet_aton(address)
except socket.error:
return False
return address.count('.') == 3
except socket.error: # not a valid address
return False
return True
def is_valid_ipv6_address(address):
try:
socket.inet_pton(socket.AF_INET6, address)
except socket.error: # not a valid address
return False
return True
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Sam*_*ain 61
该IPY模块(专为处理IP地址的模块)将抛出无效地址的ValueError异常.
>>> from IPy import IP
>>> IP('127.0.0.1')
IP('127.0.0.1')
>>> IP('277.0.0.1')
Traceback (most recent call last):
...
ValueError: '277.0.0.1': single byte must be 0 <= byte < 256
>>> IP('foobar')
Traceback (most recent call last):
...
ValueError: invalid literal for long() with base 10: 'foobar'
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然而,就像Dustin的回答一样,它会接受"4"和"192.168"之类的东西,因为如上所述,这些是IP地址的有效表示.
如果您使用的是Python 3.3或更高版本,它现在包含ipaddress模块:
>>> import ipaddress
>>> ipaddress.ip_address('127.0.0.1')
IPv4Address('127.0.0.1')
>>> ipaddress.ip_address('277.0.0.1')
Traceback (most recent call last):
File "<stdin>", line 1, in <module>
File "/usr/lib/python3.3/ipaddress.py", line 54, in ip_address
address)
ValueError: '277.0.0.1' does not appear to be an IPv4 or IPv6 address
>>> ipaddress.ip_address('foobar')
Traceback (most recent call last):
File "<stdin>", line 1, in <module>
File "/usr/lib/python3.3/ipaddress.py", line 54, in ip_address
address)
ValueError: 'foobar' does not appear to be an IPv4 or IPv6 address
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对于Python 2,如果安装python-ipaddress,则可以使用ipaddress获得相同的功能:
pip install ipaddress
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该模块与Python 2兼容,并提供了与Python 3.3之后的Python标准库中包含的ipaddress模块非常相似的API.更多细节在这里.在Python 2中,您需要将IP地址字符串显式转换为unicode : ipaddress.ip_address(u'127.0.0.1')
.
Yoh*_*ann 53
从Python 3.4开始,检查IPv6或IPv4地址是否正确的最佳方法是使用Python标准库模块ipaddress
- IPv4/IPv6操作库sa https://docs.python.org/3/library/ipaddress. html完整的文档.
示例:
#!/usr/bin/env python
import ipaddress
import sys
try:
ip = ipaddress.ip_address(sys.argv[1])
print('%s is a correct IP%s address.' % (ip, ip.version))
except ValueError:
print('address/netmask is invalid: %s' % sys.argv[1])
except:
print('Usage : %s ip' % sys.argv[0])
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对于其他版本:Github,phihag/Philipp Hagemeister,"Python 3.3的旧版Python版ipaddress",https://github.com/phihag/ipaddress
来自phihag的后端可以在例如Anaconda Python 2.7中获得,并且包含在安装程序中.sa https://docs.continuum.io/anaconda/pkg-docs
要用pip安装:
pip install ipaddress
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sa:ipaddress 1.0.17,"IPv4/IPv6操作库","3.3+ ipaddress模块的端口",https: //pypi.python.org/pypi/ipaddress/1.0.17
Mar*_*rot 43
def is_valid_ip(ip):
"""Validates IP addresses.
"""
return is_valid_ipv4(ip) or is_valid_ipv6(ip)
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IPv4的:
def is_valid_ipv4(ip):
"""Validates IPv4 addresses.
"""
pattern = re.compile(r"""
^
(?:
# Dotted variants:
(?:
# Decimal 1-255 (no leading 0's)
[3-9]\d?|2(?:5[0-5]|[0-4]?\d)?|1\d{0,2}
|
0x0*[0-9a-f]{1,2} # Hexadecimal 0x0 - 0xFF (possible leading 0's)
|
0+[1-3]?[0-7]{0,2} # Octal 0 - 0377 (possible leading 0's)
)
(?: # Repeat 0-3 times, separated by a dot
\.
(?:
[3-9]\d?|2(?:5[0-5]|[0-4]?\d)?|1\d{0,2}
|
0x0*[0-9a-f]{1,2}
|
0+[1-3]?[0-7]{0,2}
)
){0,3}
|
0x0*[0-9a-f]{1,8} # Hexadecimal notation, 0x0 - 0xffffffff
|
0+[0-3]?[0-7]{0,10} # Octal notation, 0 - 037777777777
|
# Decimal notation, 1-4294967295:
429496729[0-5]|42949672[0-8]\d|4294967[01]\d\d|429496[0-6]\d{3}|
42949[0-5]\d{4}|4294[0-8]\d{5}|429[0-3]\d{6}|42[0-8]\d{7}|
4[01]\d{8}|[1-3]\d{0,9}|[4-9]\d{0,8}
)
$
""", re.VERBOSE | re.IGNORECASE)
return pattern.match(ip) is not None
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IPv6的:
def is_valid_ipv6(ip):
"""Validates IPv6 addresses.
"""
pattern = re.compile(r"""
^
\s* # Leading whitespace
(?!.*::.*::) # Only a single whildcard allowed
(?:(?!:)|:(?=:)) # Colon iff it would be part of a wildcard
(?: # Repeat 6 times:
[0-9a-f]{0,4} # A group of at most four hexadecimal digits
(?:(?<=::)|(?<!::):) # Colon unless preceeded by wildcard
){6} #
(?: # Either
[0-9a-f]{0,4} # Another group
(?:(?<=::)|(?<!::):) # Colon unless preceeded by wildcard
[0-9a-f]{0,4} # Last group
(?: (?<=::) # Colon iff preceeded by exacly one colon
| (?<!:) #
| (?<=:) (?<!::) : #
) # OR
| # A v4 address with NO leading zeros
(?:25[0-4]|2[0-4]\d|1\d\d|[1-9]?\d)
(?: \.
(?:25[0-4]|2[0-4]\d|1\d\d|[1-9]?\d)
){3}
)
\s* # Trailing whitespace
$
""", re.VERBOSE | re.IGNORECASE | re.DOTALL)
return pattern.match(ip) is not None
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IPv6版本使用" (?:(?<=::)|(?<!::):)
",可以在(?(?<!::):)
支持具有环视功能的条件的正则表达式引擎上替换为" ".(即PCRE,.NET)
编辑:
EDIT2:
我找到了一些链接,讨论如何使用正则表达式解析IPv6地址:
EDIT3:
最后设法编写了一个通过所有测试的模式,我也很高兴.
Grz*_*ywo 14
我希望它足够简单和pythonic:
def is_valid_ip(ip):
m = re.match(r"^(\d{1,3})\.(\d{1,3})\.(\d{1,3})\.(\d{1,3})$", ip)
return bool(m) and all(map(lambda n: 0 <= int(n) <= 255, m.groups()))
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小智 7
我必须给马库斯·贾德罗特(Markus Jarderot)的帖子提供很多信誉 - 我的大多数帖子都是从他的文章中获得灵感.
我发现Markus的答案仍然没有通过他的回答引用的Perl脚本中的一些IPv6示例.
这是我的正则表达式,它传递了Perl脚本中的所有示例:
r"""^
\s* # Leading whitespace
# Zero-width lookaheads to reject too many quartets
(?:
# 6 quartets, ending IPv4 address; no wildcards
(?:[0-9a-f]{1,4}(?::(?!:))){6}
(?:25[0-4]|2[0-4]\d|1\d\d|[1-9]\d|\d)
(?:\.(?:25[0-4]|2[0-4]\d|1\d\d|[1-9]\d|\d)){3}
|
# 0-5 quartets, wildcard, ending IPv4 address
(?:(?:[0-9a-f]{1,4}(?::(?!:))){0,4}[0-9a-f]{1,4})?
(?:::(?!:))
(?:25[0-4]|2[0-4]\d|1\d\d|[1-9]\d|\d)
(?:\.(?:25[0-4]|2[0-4]\d|1\d\d|[1-9]\d|\d)){3}
|
# 0-4 quartets, wildcard, 0-1 quartets, ending IPv4 address
(?:(?:[0-9a-f]{1,4}(?::(?!:))){0,3}[0-9a-f]{1,4})?
(?:::(?!:))
(?:[0-9a-f]{1,4}(?::(?!:)))?
(?:25[0-4]|2[0-4]\d|1\d\d|[1-9]\d|\d)
(?:\.(?:25[0-4]|2[0-4]\d|1\d\d|[1-9]\d|\d)){3}
|
# 0-3 quartets, wildcard, 0-2 quartets, ending IPv4 address
(?:(?:[0-9a-f]{1,4}(?::(?!:))){0,2}[0-9a-f]{1,4})?
(?:::(?!:))
(?:[0-9a-f]{1,4}(?::(?!:))){0,2}
(?:25[0-4]|2[0-4]\d|1\d\d|[1-9]\d|\d)
(?:\.(?:25[0-4]|2[0-4]\d|1\d\d|[1-9]\d|\d)){3}
|
# 0-2 quartets, wildcard, 0-3 quartets, ending IPv4 address
(?:(?:[0-9a-f]{1,4}(?::(?!:))){0,1}[0-9a-f]{1,4})?
(?:::(?!:))
(?:[0-9a-f]{1,4}(?::(?!:))){0,3}
(?:25[0-4]|2[0-4]\d|1\d\d|[1-9]\d|\d)
(?:\.(?:25[0-4]|2[0-4]\d|1\d\d|[1-9]\d|\d)){3}
|
# 0-1 quartets, wildcard, 0-4 quartets, ending IPv4 address
(?:[0-9a-f]{1,4}){0,1}
(?:::(?!:))
(?:[0-9a-f]{1,4}(?::(?!:))){0,4}
(?:25[0-4]|2[0-4]\d|1\d\d|[1-9]\d|\d)
(?:\.(?:25[0-4]|2[0-4]\d|1\d\d|[1-9]\d|\d)){3}
|
# wildcard, 0-5 quartets, ending IPv4 address
(?:::(?!:))
(?:[0-9a-f]{1,4}(?::(?!:))){0,5}
(?:25[0-4]|2[0-4]\d|1\d\d|[1-9]\d|\d)
(?:\.(?:25[0-4]|2[0-4]\d|1\d\d|[1-9]\d|\d)){3}
|
# 8 quartets; no wildcards
(?:[0-9a-f]{1,4}(?::(?!:))){7}[0-9a-f]{1,4}
|
# 0-7 quartets, wildcard
(?:(?:[0-9a-f]{1,4}(?::(?!:))){0,6}[0-9a-f]{1,4})?
(?:::(?!:))
|
# 0-6 quartets, wildcard, 0-1 quartets
(?:(?:[0-9a-f]{1,4}(?::(?!:))){0,5}[0-9a-f]{1,4})?
(?:::(?!:))
(?:[0-9a-f]{1,4})?
|
# 0-5 quartets, wildcard, 0-2 quartets
(?:(?:[0-9a-f]{1,4}(?::(?!:))){0,4}[0-9a-f]{1,4})?
(?:::(?!:))
(?:(?:[0-9a-f]{1,4}(?::(?!:))){0,1}[0-9a-f]{1,4})?
|
# 0-4 quartets, wildcard, 0-3 quartets
(?:(?:[0-9a-f]{1,4}(?::(?!:))){0,3}[0-9a-f]{1,4})?
(?:::(?!:))
(?:(?:[0-9a-f]{1,4}(?::(?!:))){0,2}[0-9a-f]{1,4})?
|
# 0-3 quartets, wildcard, 0-4 quartets
(?:(?:[0-9a-f]{1,4}(?::(?!:))){0,2}[0-9a-f]{1,4})?
(?:::(?!:))
(?:(?:[0-9a-f]{1,4}(?::(?!:))){0,3}[0-9a-f]{1,4})?
|
# 0-2 quartets, wildcard, 0-5 quartets
(?:(?:[0-9a-f]{1,4}(?::(?!:))){0,1}[0-9a-f]{1,4})?
(?:::(?!:))
(?:(?:[0-9a-f]{1,4}(?::(?!:))){0,4}[0-9a-f]{1,4})?
|
# 0-1 quartets, wildcard, 0-6 quartets
(?:[0-9a-f]{1,4})?
(?:::(?!:))
(?:(?:[0-9a-f]{1,4}(?::(?!:))){0,5}[0-9a-f]{1,4})?
|
# wildcard, 0-7 quartets
(?:::(?!:))
(?:(?:[0-9a-f]{1,4}(?::(?!:))){0,6}[0-9a-f]{1,4})?
)
(?:/(?:1(?:2[0-7]|[01]\d)|\d\d?))? # With an optional CIDR routing prefix (0-128)
\s* # Trailing whitespace
$"""
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我还整理了一个Python脚本来测试所有这些IPv6示例; 它位于Pastebin上,因为它太大而无法在此发布.
您可以使用"[result] = [example]"形式的测试结果和示例参数运行脚本,如下所示:
python script.py Fail=::1.2.3.4: pass=::127.0.0.1 false=::: True=::1
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或者您可以通过指定无参数来简单地运行所有测试,如下所示:
python script.py
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无论如何,我希望这有助于其他人!
我想这会做到......
def validIP(address):
parts = address.split(".")
if len(parts) != 4:
return False
for item in parts:
if not 0 <= int(item) <= 255:
return False
return True
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小智 6
将 IPv4 地址视为“ip”。
if re.match(r'^((\d{1,2}|1\d{2}|2[0-4]\d|25[0-5])\.){3}(\d{1,2}|1\d{2}|2[0-4]\d|25[0-5])$', ip):
print "Valid IP"
else:
print "Invalid IP"
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