php*_*015 3 php mysql database random
我正在使用PHP和MYSQL构建一个简单的测验程序.
测验旨在一次显示一个问题; 问题是多项选择(每个问题有4个可能的答案)
如果玩家选择了正确的玩家,他会进入下一个问题; 如果他选错了,测验就结束了.
首先,我设计了如下测验:
(1)创建了一个数据库表,其中包含1500个问题.该表包含以下列:
ID (primary key)
QUESTION (the question itself)
A1 (first answer)
A2 (second answer)
A3 (third answer)
A4 (fourth answer)
CORRECT (the correct answer --- which is one of the above A1 to A4)
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(2)然后,我的PHP代码被设计为以SEQUENTIAL顺序逐个选择问题(使用ID作为参考).
因此,当用户开始播放时,他从问题1开始,然后问题2等等.
(3)为了使它更有趣,当用户在我的测验网站上注册为播放器时,我向数据库(begin_id)添加了一个额外的列,其默认值为"1".每次用户回答问题时,都会使用该问题的"ID"更新此列.意思是,它记录用户回答的最后一个问题(无论是错误还是正确).这样:下次用户登录并播放测验时,他不会从问题1开始.相反,他从列表中的NEXT问题开始.(意思是,用户永远不会看到同一个问题两次!)
这是代码:
// Query database
$get_question = "SELECT * from questions_table where id = $begin_id";
$result_get_question = mysqli_query($conn, $get_question);
$row_get_question = mysqli_fetch_array($result_get_question);
// Assign database response to variables
$question = $row_get_question['question'];
$a1 = $row_get_question['a1'];
$a2 = $row_get_question['a2'];
$a3 = $row_get_question['a3'];
$a4 = $row_get_question['a4'];
$correct = $row_get_question['correct'];
// Check user answer
if (isset($_POST['submit'])) {
$selected_radio = $_POST['response'];
if ($selected_radio == $correct)
echo "THAT ANSWER IS CORRECT";
else
echo "THAT ANSWER IS WRONG!";
}
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而且,一切都很美妙!!
现在,我决定让它更"高效"; 我没有按顺序选择问题,而是决定简单地修改我的PHP-SELECT语句,随意选择问题.
这很容易,特别是因为有很多在线教程如何完成.
这是我使用的代码(最简单的代码):
SELECT * from questions_table order by rand() limit 1;
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就选择随机问题而言,这是有效的.但是,有些事情是错误的:无论用户选择什么答案,总是错误的答案!
出于某种原因,从数据库中选择随机问题已经弄乱了我的PHP代码中的" 正确答案/错误答案 "逻辑.
不知道出了什么问题.
UPDATE
Run Code Online (Sandbox Code Playgroud)$get_question = "SELECT * from questions_table where id = $begin_id"; $result_get_question = mysqli_query($conn,$get_question); $row_get_question = mysqli_fetch_array($result_get_question); $question_id = $row_get_question['question_id']; $question = $row_get_question['question']; $a1 = $row_get_question['a1']; $a2 = $row_get_question['a2']; $a3 = $row_get_question['a3']; $a4 = $row_get_question['a4']; $correct = $row_get_question['correct'];Run Code Online (Sandbox Code Playgroud)<br> <form method ="post" action =""> <input type="radio" name="response" value="<?=$a1?>"><?=$a1?><br> <input type="radio" name="response" value="<?=$a2?>"><?=$a2?><br> <input type="radio" name="response" value="<?=$a3?>"><?=$a3?><br> <input type="radio" name="response" value="<?=$a4?>"><?=$a4?><br> <input type="hidden" name="question_id" value="<?= echo $question_id?>" /> <br> <Input type = "submit" Name = "submit" Value = "Answer"> </form>
当您向用户提出问题时,会从数据库中随机选择一个问题.
然后,用户提交您的表单,随机选择另一个问题,这是您用来检查答案的问题,而不是您向用户询问的问题.
您需要在表单中添加一个包含问题ID的隐藏输入
<input type="hidden" name="question_id" value="<?php echo $question_id ?>" />
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然后当您检查答案时,请务必从数据库中获取正确的问题
代码看起来像这样
<?php
// Check user answer for previous question
if (isset($_POST['submit'])) {
// Retrieve the id of the question you asked
$previous_question_id = (int) $_POST['question_id']; // cast to integer to prevent sql injection.
// Query database
$get_question = "SELECT * from questions_table where id = $previous_question_id";
$result_get_question = mysqli_query($conn, $get_question);
$row_get_question = mysqli_fetch_array($result_get_question);
// Assign database response to variables
$correct = $row_get_question['correct'];
$selected_radio = $_POST['response'];
if ($selected_radio == $correct)
echo "THAT ANSWER IS CORRECT";
else
echo "THAT ANSWER IS WRONG!";
}
// Load new question to ask to the user
$get_question = "SELECT * from questions_table order by rand() limit 1";
$result_get_question = mysqli_query($conn,$get_question);
$row_get_question = mysqli_fetch_array($result_get_question);
// assign thing we want to print in the template to variable
$question_id = $row_get_question['question_id'];
$question = $row_get_question['question'];
$a1 = $row_get_question['a1'];
$a2 = $row_get_question['a2'];
$a3 = $row_get_question['a3'];
$a4 = $row_get_question['a4'];
?>
<PASTE YOUR TEMPLATE HERE>
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